我在sql中有一个帖子表,其作者列已连接到用户表。我使用单个SQL查询从帖子表中获取帖子,并使用用户表中的作者姓名。我的帖子表格如下:
+----+-----------------+-----------------+--------+
| id | title | label | author |
+----+-----------------+-----------------+--------+
| 22 | Post 1 | post-1 | 2 |
| 24 | Post 2 | post-2 | 4 |
| 25 | Post 3 | post-3 | 4 |
| 26 | Post 4 | post-4 | 5 |
| 27 | Post 5 | post-5 | 6 |
| 28 | Post 6 | post-6 | 2 |
| 29 | Post 7 | post-7 | 2 |
| 30 | Post 8 | post-8 | 2 |
| 32 | Post 9 | post-9 | 2 |
+----+-----------------+-----------------+--------+
我使用此sql查询来获取帖子标题,标签及其作者姓名和姓氏。
SELECT `posts`.id, `posts`.title, `posts`.label, users.id AS author, users.name AS name, users.surname AS surname
FROM `posts`
INNER JOIN users
ON users.id = posts.author
ORDER BY `date` DESC;
这完全正常,但它只返回已知作者id为2的帖子,因为在users表中我只有作者ID 2.缺少其他作者(4,5和6)。因此,我没有显示具有未知作者的帖子,而是希望将它们显示为null作为其名称和姓氏变量。顺便说一句,结果是;
+----+----------------+----------------+--------+------+---------+
| id | title | label | author | name | surname |
+----+----------------+----------------+--------+------+---------+
| 32 | Post 9 | post-9 | 2 | Jack | Smith |
| 30 | Post 8 | post-8 | 2 | Jack | Smith |
| 29 | Post 7 | post-7 | 2 | Jack | Smith |
| 28 | Post 6 | post-6 | 2 | Jack | Smith |
| 22 | Post 1 | post-1 | 2 | Jack | Smith |
+----+----------------+----------------+--------+------+---------+
答案 0 :(得分:2)
您必须使用LEFT JOIN而不是INNER JOIN。内部联接的结果只显示在两个表中表示的实体。当实体在第一个表中表示而不在第二个表中时,左连接添加空值。
答案 1 :(得分:1)
尝试使用左连接:
再一次创建外键约束,同时引用另一个表值。
SELECT `posts`.id, `posts`.title, `posts`.label, posts.id AS author,
users.name AS name, users.surname AS surname
FROM `posts`
LEFT JOIN users
ON users.id = posts.author
ORDER BY `date` DESC;