java.lang.IllegalStateException：executePendingTransactions的递归入口

Question

首先，我尝试了几乎所有关于 StackOverflow 的答案来试试这个问题。!!但没有任何作用。我正在分享我的节目。请看一下，让我知道如何解决这个问题。

以前我使用的是 getFragmentManger（）方法，但它会抛出相同的异常。然后我尝试了这个 getChildFragmentManager（）方法。但它仍然显示了同样的例外.. !!

这是代码：

public class FragmentC extends Fragment {

 private final List<String> mListGroup = new ArrayList<String>();
 private ViewPager viewPager;
 private ListPagerAdapter groupsPagesAdapter;
 private PagerTabStrip pagerTabs;
 public FragmentC() {
    // Required empty public constructor
}
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
        viewPager = (ViewPager) ((Activity)  parentContext).findViewById(R.id.pager);


    groupsPagesAdapter = new ListPagerAdapter(getChildFragmentManager(), viewPager); // Here I made the change, But still fails 


    pagerTabs = (PagerTabStrip) ((Activity) parentContext).findViewById(R.id.tabstrip);
    pagerTabs.setTabIndicatorColorResource(R.color.vert_manu);
    pagerTabs.setNonPrimaryAlpha(PAGER_TAB_SECONDARY_ALPHA);

    mListGroup.add(getString(R.string.contact_list_all_contact));
    mListGroup.add(getString(R.string.contact_list_no_group));
    groupsPagesAdapter.notifyDataSetChanged();
    View v= inflater.inflate(R.layout.contactlist, container, false);

    return v;
}

private class ListPagerAdapter extends FragmentPagerAdapter {


public ListPagerAdapter(final FragmentManager fm, final ViewPager viewPager) {
    super(fm);
    viewPager.setAdapter(this);
}

@Override
public Fragment getItem(int position) {
    String group = mListGroup.get(position);
    ContactListFragment f = ContactListFragment.newInstance(group);
    f.setListAdapter(getContactListAdapter(group));
    return f;
}

@Override
public int getCount() {
    return mListGroup.size();
}

@Override
public String getPageTitle(int position) {
    return mListGroup.get(position);
}

}
}