所以我在这里遇到了麻烦。当我为numStudents输入1但是得到分段错误时,该程序工作得很好:11当我再输入1为numstudents时。我是否在动态分配方面做错了什么?我只是失去了我能想到的一切。
#include <iostream>
#include <string>
#include <cstdlib>
#include <iomanip>
using namespace std;
//Structure Declaration
struct Student
{
string name;
long long ID;
double *score;
};
//Function prototypes
void calcAvg (int loc, Student test[], double average[], int tests);
int main()
{
int numStudents, numTests; //Get from user
double *averages; //For Dynamic allocation of averages
Student *info; //For Dynamic Allocation
cout << "Enter the number of students you will enter ";
cin >> numStudents;
info = new Student[numStudents];
averages = new double[numStudents];
cout << "\nEnter the number of tests that were taken by the students ";
cin >> numTests;
info->score = new double[numTests];
for(int s = 0; s < numStudents; s++)
{
cout << "Enter student #" << (s+1) << "'s name ";
cin.ignore();
getline(cin, info[s].name);
cout << "Enter " << info[s].name << "'s ID number ";
cin >> info[s].ID;
cout << endl;
for(int t = 0; t < numTests; t++)
{
cout << "\nEnter " << info[s].name << "'s score for test #" <<(t+1) << " ";
cin >> info[s].score[t];
while(info[s].score[t] > 100 || info[s].score[t] < 0)
{
cout << "The score you entered is invalid, try again. ";
cin >> info[s].score[t];
}
}
calcAvg(s, info, averages, numTests);
}
return 0;
}
void calcAvg (int loc, Student test[], double average[], int tests)
{
double total = 0;
for(int i = 0; i < tests; i++)
{
total += test[loc].score[i];
}
average[loc] = total/tests;
cout << average[loc] << endl;
}
答案 0 :(得分:3)
你需要为每个学生重复这个
info->score = new double[numTests];
所以你可以把它移到循环中:
for(int s = 0; s < numStudents; s++)
{
info[s].score = new double[numTests];
...
}
但这一切都非常容易出错 - 我建议你研究一下可以为你处理所有这些问题的结构std::vector
。