Question

我需要获得花费更多资金但不重复的前2名客户。

我有这段代码：

Select DISTINCT Top 2 Clientes.Nome, Clientes.NCartao, Vendas.ValorCIva 
from Clientes AS Cli, Vendas
INNER JOIN Clientes ON Clientes.IdCliente = Vendas.IdCliente
order by Vendas.ValorCIva DESC

我有这个结果：

Client          Number  Total
José Pinto      123456  8,48
José Pinto      123456  6,52
Joao Ferreira   564789  5,75

但我想要这个：

Client          Number  Total
José Pinto      123456   15
Joao Ferreira   564789  5,75

Answer 1

一种方法：

select Top 2 Clientes.Nome, Clientes.NCartao, sum(Vendas.ValorCIva) ValorCIva 
from Clientes AS Cli, Vendas INNER JOIN Clientes ON Clientes.IdCliente = Vendas.IdCliente 
group by Clientes.Nome, Clientes.NCartao
order by sum(Vendas.ValorCIva) DESC

Answer 2

如果你不想重复那个客户端放置一个GROUP BY，那么它会自动显示每个客户端而不会重复，就像这样......

Select Top 2 Clientes.Nome, Clientes.NCartao, Vendas.ValorCIva 
FROM Clientes AS Cli, Vendas
INNER JOIN Clientes ON Clientes.IdCliente = Vendas.IdCliente
GROUP BY Clientes.Nome
ORDER BY Clientes.Nome

使用DISTINCT名称SQL SERVER选择TOP 2

2 个答案: