Question

我正在使用python来传输数据，我正在尝试将读入的数据复制到文本文件中。我使用的代码工作正常，虽然我需要这个不断循环。我认为while循环应该这样做，但输出只是挂起。我哪里错了？

import socket
import sys
import time

#Create a TCP/IP socket
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)


#bind the socket to the port
server_address = ('192.168.1.90', 10000)
print >> sys.stderr, 'connecting to %s port %s' % server_address
sock.connect(server_address)

while True:

try:
    #send data
    message = 'Making Connection . . .'
    print >> sys.stderr, '"%s"' % message
    sock.sendall(message)

    #look for response
    amount_received = 0
    amount_expected = 4096

    while amount_received < amount_expected:
        data = sock.recv(4096)
            amount_received += len(data)
        print >> sys.stderr, 'received "%s"' % data
    with open ('SPI.txt', 'a') as output:
            output.write(data)
    time.sleep(0.5)

finally:
       print >> sys.stderr, 'closing socket'
       sock.close()

Answer 1

sock.recv是一个阻塞调用，只有在有任何数据可供读取时才会返回。您需要使用不同的线程来回收套接字上的数据或使用非阻塞套接字。

TCP中的客户端挂起错误

1 个答案: