Question

我将JSON字符串发布到接受我创建的对象的控制器方法。该对象有两个属性：一个int列表和一个字符串。我想在js中创建JSON字符串，通过AJAX发布到控制器。我找不到一种在JSON中动态创建List的方法。

这是我想要构建JSON的地方

    var ApplicantIDs = [];
    var RejectionReason = $("#SelectedRejectReason").val();
    ApplicantIDs = $("#RejectIDs").val();
    var Rejection;
    jQuery.each(ApplicantIDs, function(i) {

        //add ApplicantIDs to Rejection object
    });

    //add RejectionReason to Rejection object

    RejectApplicants(Rejection);

这是AJAX帖子

 function RejectApplicants(Rejection) {

    jQuery.ajax({
        type: "POST",
        url: '@Url.Action("RejectApplicants", "Home")',
        data: JSON.stringify(Rejection),
        dataType: "json",
        contentType: "application/json",
        success: function (data) {
            if (data.redirectTo == null) {
                window.location.href = '@Url.Action("Error", "Home")';
            } else {
                alert("All selected applicants exported succesfully!");
                window.location.href = data.redirectTo;
            }
        },
        error: function () {
            window.location.href = '@Url.Action("Error", "Home")';
        }
    });

}

控制器

    [HttpPost]
    public ActionResult RejectApplicants(Rejection myRejection)

我的拒绝对象

public class Rejection
{
    public List<int> ApplicantIDs { get; set; }
    public string RejectionReason { get; set; }
}

Answer 1

您可以声明对象，如下所示：

var Rejection = {
    RejectionReason: $("#SelectedRejectReason").val(),
    ApplicantIDs: $("#RejectIDs").val().split(',')
};

RejectApplicants(Rejection);

创建包含List对象的JSON字符串

1 个答案: