Question

我的视图代码在这里......什么是控制器的代码，plz任何人都可以解释。

   <td><?php $attributes = array();
      $options = array($question['Question']['opt1']);
      echo $this->Form->radio($i, $options, $attributes);?>&nbsp;</td>


    <td><?php $attributes = array();
      $options = array($question['Question']['opt2']);
      echo $this->Form->radio($i, $options, $attributes);?>&nbsp;</td>


    <td><?php $attributes = array();
      $options = array($question['Question']['opt3']);
      echo $this->Form->radio($i, $options, $attributes);?>&nbsp;</td>

    <td><?php $attributes = array();
      $options = array($question['Question']['opt4']);
      echo $this->Form->radio($i, $options, $attributes);?>&nbsp;</td>
 </tr>

 <?php endforeach; ?>
<td><?php echo $this->Form->end(__('Submit'),array('controller'=>'question')); ?></td>

Answer 1

就这么简单。在您的问题控制器中，我们要说您的表单已提交给＆＃39; / questions / yourActionMethodName＆＃39;

您的代码应该类似于：

public function yourActionMethodName(){

    if($this->request->is('post') && !empty($this->request->data)){
        $this->Question->create(); //to save a new record
        $this->Question->save($this->request->data);
    }
}

这应该创建一个新的新记录，设置字段＆＃39; opt1＆＃39;的数据库列值。到用户选择的值。我不确定你要解决的是什么情况。这应该可以让您了解保存到数据库的方式。告诉我有关案例的更多信息，我可以编辑代码以满足您的需求。

Answer 2

您需要输入此模型和名称

   <td><?php $attributes = array();
      $options = array($question['Question']['opt1']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>


    <td><?php $attributes = array();
      $options = array($question['Question']['opt2']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>


    <td><?php $attributes = array();
      $options = array($question['Question']['opt3']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>

    <td><?php $attributes = array();
      $options = array($question['Question']['opt4']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>
 </tr>

<?php endforeach; ?>
<td><?php echo $this->Form->end(__('Submit')); ?></td>

在你的控制器中如果需要保存很多字段，你需要使用saveAll或saveMany dep

public function Name(){

    if($this->request->is('post') && !empty($this->request->data)){
        $this->Question->create();
        $this->Question->save($this->request->data);
    }
}

Answer 3

您必须在控制器中加载模型才能在数据库中创建新记录你的观点看起来像这样：

<?php echo $this->Form->create('Question');?>
<td><?php $attributes = array();
      $options = array($question['Question']['opt1']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>


    <td><?php $attributes = array();
      $options = array($question['Question']['opt2']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>


    <td><?php $attributes = array();
      $options = array($question['Question']['opt3']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>

    <td><?php $attributes = array();
      $options = array($question['Question']['opt4']);
      echo $this->Form->radio('Model.'.$i.'.name', $options, $attributes);?>&nbsp;</td>
 </tr>

<?php endforeach; ?>
<td><?php echo $this->Form->end(__('Submit')); ?></td>

现在在您的控制器中，您必须在创建新记录之前加载模型

public function NameOfYourFunction(){

    $this->loadModel('Question');

    if ($this->request->is('post')) {                
            if ($this->Question->save($this->request->data)) {
                  $this->Session->setFlash(__('Information save succesfully.'));
                  return $this->redirect(array('action' => 'index'));
            }
        }

}

我希望我帮助你

在cakephp中选择单选按钮后如何提交值？

3 个答案: