Question

我有以下PostgreSQL函数返回v_result，如下所示

CREATE OR REPLACE FUNCTION public.get_email_text(p_notification_id integer)
  RETURNS character varying AS 
$BODY$
DECLARE
    v_result varchar;

BEGIN  

    SELECT email_text INTO  v_result 
    FROM  public.notification 
    WHERE notification_id = p_notification_id;
    RETURN v_result;

END;
$BODY$
  LANGUAGE plpgsql VOLATILE
  COST 100;
  ALTER FUNCTION  public.get_email_text(integer) OWNER TO test;

执行此操作时：

select public.get_email_text(4673);

它产生的输出如下：

This email is to notify you that for one or more records has been Requested. Please follow the link below to go directly to this records.  <BR/> <BR/> <BR/>Records Id : Record Name : Subrecord Id : Subrecord Name<BR/><ul><a href = http://localhost:8080/myproject/ShowRecord.action?recordsVO.recordId=3324&recordId=3324&status
=Clearance Requested >3324 </a> : DEV: test record : 2999 : Clearance</ul>

在我返回v_result之前，我想从输出中删除它：

This email is to notify you that for one or more records has been Requested.

所以剩下的只剩下了：

Please follow the link below to go directly to this records ...

Answer 1

在您不需要时使用更简单，更便宜的普通replace()功能更强大，更昂贵的正则表达式函数regexp_replace()（将点（.）解释为任何字符的占位符）。

另外，我建议这个更简单的sql函数：

CREATE OR REPLACE FUNCTION public.get_email_text(p_notification_id integer)
  RETURNS text AS 
$func$
   SELECT replace(email_text, 'This email is to notify you that ...', '')
   FROM   public.notification 
   WHERE  notification_id = p_notification_id
$func$  LANGUAGE sql;
ALTER FUNCTION public.get_email_text(integer) OWNER TO test;

Answer 2

我用过下面的

select regexp_replace(v_result, 'This email is to notify you that for one or more titles the Clearance has been Requested.', '') INTO
        v_popup_text;

附加或更改proc的返回

2 个答案: