Question

您好，我在Sql server中有50个表。

所有表都在加入。

对于前。

国家/地区表

PKCountryID
Name

州表

PKStateID
FKCountryID
Name

城市表

PKCityID
FKStateID
Name

员工表

PKID
FIrstName
LastName
FKCityID

所以我想要所有表格的所有列。为此，我在Fiddle下面写。

Fiddle

这会给我一些结果

COLUMN_NAME

PKEmployeeID
Name
FKCityID

但我想要这样的结果。

COLUMN_NAME

 PKEmployeeID
 Name
-FKCityID
     PKCityID
     Name
    -FKStateID
          PKStateID
          Name
         -FKCountryID
               PKCountryID
               Name
  PKCityID
  Name
 -FKStateID
      PKStateID
      Name
     -FKCountryID
            PKCountryID
            Name

  PKStateID
  Name
 -FKCountryID
       PKCountryID
       Name

  PKCountryID
  Name

Answer 1

您可以尝试递归公用表表达式。类似的东西：

;
WITH    cte
          AS ( SELECT   c.name AS column_name ,
                       -- t.object_id AS tableid ,
                        0 AS treelevel
               FROM     sys.tables AS t
                        INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
               WHERE    t.object_id = 754101727
               UNION ALL
               SELECT   c.name ,-- + ' ' + f.referenced_column_name AS column_name ,
                        --t.object_id AS tableid ,
                        treelevel + 1
               FROM     ( SELECT    f.name AS foreign_key_name ,
                                    OBJECT_NAME(f.parent_object_id) AS table_name ,
                                    COL_NAME(fc.parent_object_id,
                                             fc.parent_column_id) AS constraint_column_name ,
                                    OBJECT_NAME(f.referenced_object_id) AS referenced_object ,
                                    COL_NAME(fc.referenced_object_id,
                                             fc.referenced_column_id) AS referenced_column_name ,
                                    is_disabled ,
                                    delete_referential_action_desc ,
                                    update_referential_action_desc ,
                                    f.referenced_object_id AS parent_object_id
                          FROM      sys.foreign_keys AS f
                                    INNER JOIN sys.foreign_key_columns AS fc ON f.object_id = fc.constraint_object_id
                        ) f
                        JOIN cte ON cte.column_name = f.constraint_column_name
                        JOIN sys.tables AS t ON t.object_id = f.parent_object_id
                        INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID

                        --IN ORDER TO STOP LOOP AT SPECIFIC LEVEL YOU NEED:
                        WHERE treelevel < 2

             )
    SELECT  
           --IN ORDER TO REMOVE DOUBLINGS ADD DISTINCT
            DISTINCT *
    FROM    cte
    ORDER BY treelevel, tableid

您可以在此处找到递归作用：Sql server CTE and recursion example

获取所有表和参考表的所有列的列表，参见表的引用

1 个答案: