Question

当我在表单中输入值时，转换器没有显示答案。它会显示弹出警告“你必须输入一个32到40之间的数字”〜谢谢

<HTML>
    <HEAD>
    <TITLE>Bra Size to Chest Size Converter - CM</TITLE>

    <SCRIPT LANGUAGE="JavaScript">
        function CalculateSum(Atext, Btext, form)
        {
            var A = BratoNum(Btext);
            var B = parseFloat(CuptoNum(Btext));
            form.Answer.value = A + B;
        }


        function ClearForm(form)
        {
            form.input_A.value = "";
            form.input_B.value = "";
            form.Answer.value = "";
        }

        function BratoNum(str)
        {
            switch(str.toUpperCase()) {
                case "32": return 70;
                case "34": return 75;
                case "36": return 80;
                case "38": return 85;
                case "40": return 90;
                default:  alert('You must enter a number between 32 and 40!');
                return 'X';
            }
        }

        function CuptoNum(str)
        {
            switch(str.toUpperCase()) {
                case "A": return 4;
                case "B": return 5;
                case "C": return 6;
                case "D": return 7;
                case "E": return 8;
                case "F": return 9;
                default:  alert('You must enter a letter between A and F!');
                return 'X';
            }
        }

// end of JavaScript functions -->
</SCRIPT>
</HEAD>

<BODY>

    <P><FONT SIZE="+2">Bra Size to Chest Size Converter</FONT></P>

    <FORM NAME="Calculator" METHOD="post">
    <P>Enter Bra Size: <INPUT TYPE=TEXT NAME="input_A" SIZE=8></P>

    <P>Enter Cup Size: <INPUT TYPE=TEXT NAME="input_B" SIZE=8></P>

    <P><INPUT TYPE="button" VALUE="Get Chest Size" name="AddButton" onClick="CalculateSum(this.form.input_A.value, this.form.input_B.value, this.form)"></P>

    <P>Your Chest Size is <INPUT TYPE=TEXT NAME="Answer" SIZE=8> inch</P>
    <P><INPUT TYPE="button" VALUE="Clear" name="ClearButton" onClick="ClearForm(this.form)"></P>
    </FORM>

</BODY>
</HTML>

Answer 1

 var A = BratoNum(Atext);

您正在传递Btext！

Answer 2

其实你传递的是无效的 BratoNum函数的参数。那是为什么它总是进入默认情况'

var A = BratoNum(Atext);
// Here I have changed the argument , which you suppose to pass.

Javascript转换器编码错误〜显示错误

2 个答案: