我有一种情况需要执行以下操作:
公司名称:
a. Split text before and after “ - “
b. Generate the report where texts before and after “ - “ matches = exact match
c. Generate the report where texts before and after “ - “ matches = similar matches
我可以到达b点。其中我可以使用以下内容获得具有相同firsthalf和secondhalf(例如abc,inc。 - abc,inc。)名称的结果 -
RTRIM(substring(c.companyname,0,charindex('-',c.companyname)))= LTRIM(substring(c.companyname, charindex('-',c.companyname,0)+1, len(c.companyname)))
但是,我无法进行下一次报告(例如abc。 - abc OR abc,inc - abc)
有人可以帮忙吗?
答案 0 :(得分:0)
试试这个?
DECLARE @CompanyNames TABLE (
CompanyName VARCHAR(512));
INSERT INTO @CompanyNames VALUES ('Walt Disney - Walt Disney');
INSERT INTO @CompanyNames VALUES ('Fun Food - Fun Food');
INSERT INTO @CompanyNames VALUES ('Fun Food, Inc. - Fun Food');
INSERT INTO @CompanyNames VALUES ('Walt Disney - Walt Disney, Inc.');
--Split names
DECLARE @SplitNames TABLE (
MatchLeft VARCHAR(128),
MatchRight VARCHAR(128));
INSERT INTO
@SplitNames
SELECT
RTRIM(SUBSTRING(CompanyName, 0, CHARINDEX('-', CompanyName))),
LTRIM(SUBSTRING(CompanyName, CHARINDEX('-', CompanyName, 0) + 1, LEN(CompanyName)))
FROM
@CompanyNames;
--Exact matches
SELECT
MatchLeft,
MatchRight,
CASE WHEN MatchLeft = MatchRight THEN 1 ELSE 0 END AS Exact
FROM
@SplitNames;
--Inexact matches
WITH CleansedCompanyNames AS (
SELECT
MatchLeft AS OriginalMatchLeft,
MatchRight AS OriginalMatchRight,
REPLACE(REPLACE(REPLACE(MatchLeft, '.', ''), 'Inc', ''), ',', '') AS MatchLeft,
REPLACE(REPLACE(REPLACE(MatchRight, '.', ''), 'Inc', ''), ',', '') AS MatchRight
FROM
@SplitNames)
SELECT
OriginalMatchLeft,
OriginalMatchRight,
MatchLeft,
MatchRight,
CASE WHEN MatchLeft = MatchRight THEN 1 ELSE 0 END
FROM
CleansedCompanyNames;
--Using SOUNDEX
SELECT
MatchLeft,
MatchRight,
CASE WHEN DIFFERENCE(MatchLeft, MatchRight) >= 3 THEN 1 ELSE 0 END AS Score
FROM
@SplitNames;
有两种处理不精确匹配的想法:
或者,要使用原始示例,您可以将其用于SOUNDEX:
SELECT ...
WHERE
DIFFERENCE(RTRIM(substring(c.companyname,0,charindex('-',c.companyname))), LTRIM(substring(c.companyname, charindex('-',c.companyname,0)+1, len(c.companyname)))) >= 3
使用您的最新示例:
DECLARE @Company TABLE (
companyname VARCHAR(500));
INSERT INTO @Company VALUES ('Allen Limited - Allen Corporation');
INSERT INTO @Company VALUES ('Sweden Corp. - Sweden Corp.');
INSERT INTO @Company VALUES ('Alaska Limited - Alaska Limited, Inc.');
INSERT INTO @Company VALUES ('New York Inc. - New York Steel Limited');
INSERT INTO @Company VALUES ('India Plc - India Plc.');
INSERT INTO @Company VALUES ('Dubai International - Dubai International');
INSERT INTO @Company VALUES ('Nigera Falls Pvt. Ltd. - Amazing Nigeria Falls');
SELECT
c.companyname,
DIFFERENCE(RTRIM(SUBSTRING(c.companyname, 0, CHARINDEX('-', c.companyname))), LTRIM(SUBSTRING(c.companyname, CHARINDEX('-', c.companyname, 0) + 1, LEN(c.companyname)))) AS Similarity
FROM
@Company c;
结果:
companyname Similarity
Allen Limited - Allen Corporation 4
Sweden Corp. - Sweden Corp. 4
Alaska Limited - Alaska Limited, Inc. 4
New York Inc. - New York Steel Limited 4
India Plc - India Plc. 4
Dubai International - Dubai International 4
Nigera Falls Pvt. Ltd. - Amazing Nigeria Falls 1
所以它对你上一个例子的效果不是很好,但对其他人来说似乎没问题呢?