我有一个返回此的API:
{
"CODE": 200,
"EXAMS_LIST": {
"0": {
"CFU": " 9",
"RESULT": "SOSTENUTO",
"SSD": " MAT/05",
"TAF": " A",
"TEACHING": "MATEMATICA I CFU 9",
"YEAR": 1
},
"1": {
"CFU": " 4",
"RESULT": "Sufficiente",
"SSD": " L-LIN/12",
"TAF": " E",
"TEACHING": "LINGUA INGLESE (COLLOQUIO)",
"YEAR": 1
},
"2": {
"CFU": " 6",
"RESULT": "SOSTENUTO",
"SSD": " FIS/01",
"TAF": " A",
"TEACHING": "FISICA CFU 6",
"YEAR": 1
},
...........
"22": {
"CFU": " 5",
"RESULT": " ",
"SSD": " ",
"TAF": " E",
"TEACHING": "PROVA FINALE CFU 5",
"YEAR": 3
}
}
我正在尝试使用DataContractJsonSerializer类解析它...我已经用这种方式制作了支持类:
[DataContract]
public class Exam
{
[DataMember(Name = "CFU", IsRequired = true)]
private string cfu;
[DataMember(Name = "RESULT", IsRequired = true)]
private string result;
[DataMember(Name = "SSD")]
private string ssd;
[DataMember(Name = "TAF")]
private string taf;
[DataMember(Name = "TEACHING", IsRequired = true)]
private string teaching;
[DataMember(Name = "YEAR", IsRequired = true)]
private string year;
public string Cfu
{
get { return cfu; }
set { cfu = value; }
}
.........
public string Year
{
get { return year; }
set { year = value; }
}
}}
[DataContract]
public class StudyPlanResponse
{
[DataMember(Name="CODE")]
public string Code {get;set;}
[DataMember(Name = "EXAMS_LIST")]
public ExamList Exams { get; set; }
}
[DataContract]
public class ExamList
{
[DataMember(Name = "0")]
public Exam ex0 { get; set; }
[DataMember(Name = "1")]
public Exam ex1 { get; set; }
............
[DataMember(Name = "30")]
public Exam ex30 { get; set; }
}
如果我使用List它不起作用......这样,解析速度很慢......有什么解决方案吗?提前谢谢
答案 0 :(得分:0)
在您的响应对象中,EXAMS_LIST应定义为Dictionary<int, Exam>
。问题是DataContractJsonSerializer无法正确处理字典。最好的办法是使用Newtonsoft的JSON.NET。以下是您使用JSON.NET的方式:
将EXAMS_LIST更改为Dictionary<int, Exam>
[DataContract]
public class StudyPlanResponse
{
[DataMember(Name = "CODE")]
public string Code { get; set; }
[DataMember(Name = "EXAMS_LIST")]
public Dictionary<int, Exam> Exams { get; set; }
}
调用JSON.NET
StudyPlanResponse response = JsonConvert.DeserializeObject<StudyPlanResponse>(File.ReadAllText("TextFile1.json"));
答案 1 :(得分:0)
源使用的格式与Dictionary
兼容,而不是更常见的List
或Array
,因此简短的回答是使用Dictionary
反序列化EXAMS_LIST
元素。
两个答案,都使用以下结构:
public class StudyPlanResponse
{
public int CODE { get; set; }
public Dictionary<int, Exam> EXAMS_LIST { get; set; }
public class Exam
{
public string CFU { get; set; }
public string RESULT { get; set; }
public string SSD { get; set; }
public string TAF { get; set; }
public string TEACHING { get; set; }
public int YEAR { get; set; }
}
}
首先,使用JSON.Net
:
StudyPlanResponse studyplan = JsonConvert.DeserializeObject<StudyPlanResponse>(jsrc);
其次,使用DataContractJsonSerializer
:
var settings = new DataContractJsonSerializerSettings();
settings.UseSimpleDictionaryFormat = true;
DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(StudyPlanResponse), settings);
StudyPlanResponse studyplan;
using (var stream = new System.IO.MemoryStream(Encoding.UTF8.GetBytes(jsrc)))
{
studyplan = (StudyPlanResponse)ser.ReadObject(stream);
}
我个人更喜欢JSON.Net版本。一旦您通过设置对象告诉它使用简单字典格式,DataContractJsonSerializer
版本就可以工作。