Question

我是PHP OOP的新手，所以我不确定我是否会以正确的方式解决这个问题。父方法isRegistered（）将正确地查询db并在从父级调用方法时返回一个值（$ affected_rows），但是当我从中调用方法时，它只会“回显”该值（不会返回它）孩子，所以我不确定我是否错误地构建了孩子。这是我的代码：

//Log in with social credentials
if(isset($_POST["fb-reg"])) {
$fbOptions = array(
    'email' => "joe@gmail.com",
    'fbId' => "678910",
    'handler' => $handler); //the db connection
    fbRegister($fbOptions);
}

//Instantiate parent and child and get results of query
function fbRegister($fbOptions) {
$a = new newUser();
$fb = new fbUser($fbOptions);
$fb->isRegistered(); // will echo back $affected_rows
$y = isRegistered(); 
    echo $y; // does not return value of $affected_rows
}

//Parent class
class newUser {
public $email;
public $pass;
public $dbconn;
public $confirm;
public $message;

public function __construct($options) {
    $this->email = $options['email'];
    $this->pass = $options['password'];
    $this->confirm = $options['confirm'];
    $this->dbconn = $options['handler'];
    $this->message = array();
    }   
// CHECK IF USER EXISTS ====================================
public function isRegistered() {
$sql=("SELECT * FROM Test WHERE Email = :email");
$query = $this->dbconn->prepare($sql);
$query->execute(array(':email' => $this->email));
$affected_rows = $query->rowCount();
return $affected_rows; // query works but does not return value  to calling function
echo $affected_rows;  // query result will be echoed by calling function
    }
}

//Child class
class fbUser extends newUser{
public $id;
public $email;
public $dbconn;         

function __construct($fbOptions) {
    $this->id = $fbOptions['fbId'];
    $this->email = $fbOptions['email'];
    $this->dbconn = $fbOptions['handler'];
     }

public function isRegistered() {
    parent::isRegistered($this->email, $this->dbconn);
         }
}

Answer 1

我需要在子方法中返回：

return parent :: isRegistered（$ this-＆gt; email，$ this-＆gt; dbconn）;

从child调用时从PHP父方法返回值

1 个答案: