Question

我正在尝试创建一个私有方法，根据一些数据库数据进行一些计数，如下所示。

class ApplicationController < ActionController::Base
  # Prevent CSRF attacks by raising an exception.
  # For APIs, you may want to use :null_session instead.
  protect_from_forgery with: :exception

    before_action :moderation_count

    private

    def moderation_count
      @count = '';
      @count[:venues_pending] = Venue.where(:is_approved => 0).count.to_i
      @count[:venues_rejected] = Venue.where(:is_approved => 2).count.to_i
      @count[:venue_photos_pending] = VenuePhoto.where(:is_approved => 0).count.to_i
      @count[:venue_photos_rejected] = VenuePhoto.where(:is_approved => 2).count.to_i
      @count[:venue_reviews_pending] = VenueReview.where(:is_approved => 0).count.to_i
      @count[:venue_reviews_rejected] = VenueReview.where(:is_approved => 2).count.to_i
    end
end

错误：

没有将符号隐式转换为整数

Answer 1

您已使用

将@count设为空String

@count = '';

所以，当您执行@count[:venues_pending]时，Ruby会尝试将符号 :venues_pending转换为整数以访问特定索引字符串@count。这导致错误为no implicit conversion of Symbol into Integer

当您计划将实例变量@count用作Hash时，您应该将其实例化为哈希而不是空字符串。

使用@count = {};或@count = Hash.new;

Rails没有将Symbol隐式转换为Integer

1 个答案: