Question

所以，给定：

dttm = datetime.datetime.strptime("2014-06-23 13:56:30", "%Y-%m-%d %H:%M:%S")
ws['A1'] = dttm

excel中的结果是将正确的日期时间写入单元格（您可以在输入公式的位置看到它）。但是，单元格显示格式仅为MM / DD / YYYY。

我需要显示单元格＆＃34; 6/23/2014 13:56＆＃34;而不只是＆＃34; 6/23/2014＆＃34;。

如何明确格式化单元格以实现此目的？

谢谢！

修改

@alecxe此解决方案有效，正是我所要求的。我希望能够像@Woodham一样保存解决方案。不幸的是，它引发了一个typeError（请参阅注释）。有什么建议吗？

Answer 1

我将此添加为新答案，因为我没有足够的声誉来为上述内容添加评论。格式化单元格的最简单方法是使用.number_format =＆＃34;格式＆＃34;如：

value = datetime.datetime.strptime("2014-06-23 13:56:30", "%Y-%m-%d %H:%M:%S")
cell = ws['A1']
cell.value = value
cell.number_format = 'YYYY MMM DD'

这是在openpyxl（2.2.2）

中测试的

Answer 2

对于openpyxl 2.4.5，您将无法再访问NumberFormat和Style，并且必须使用NamedStyle。以下是一些示例用法：

from openpyxl.styles import NamedStyle

date_style = NamedStyle(name='datetime', number_format='DD/MM/YYYY HH:MM:MM')
ws['A1'].style = date_style

或者使用新的NamedStyle类，您可以在实例化NamedStyle后按字符串名称设置样式：

from openpyxl.styles import NamedStyle

NamedStyle(name='custom_datetime', number_format='DD/MM/YYYY HH:MM:MM')
ws['A1'].style = 'custom_datetime'

此处的文档：http://openpyxl.readthedocs.io/en/default/styles.html#creating-a-named-style

Answer 3

您可以手动设置format_code：

value = datetime.datetime.strptime("2014-06-23 13:56:30", "%Y-%m-%d %H:%M:%S")
cell = ws['A1']
cell.value = value
cell.style.number_format.format_code = 'MM/DD/YY HH:MM'

或者，您可以在单元格上调用_set_number_format()方法：

cell._set_number_format('MM/DD/YY HH:MM')

您还可以通过为单元格设置ws._styles来定义样式并重复使用它：

from openpyxl.styles import NumberFormat, Style

...

style = Style()
style.number_format = NumberFormat()
style.number_format.format_code = 'MM/DD/YY HH:MM'

ws['A1'] = value
ws._styles['A1'] = style

经过测试 - 为我工作过。

Answer 4

我相信您需要在要格式化的单元格上设置openpyxl.styles.Style。

查看documentation here，这样的事情应该有效：

dttm = datetime.datetime.strptime("2014-06-23 13:56:30", "%Y-%m-%d %H:%M:%S")
s = Style(number_format=NumberFormat('dd-mm-yyyy h:mm:ss'))

ws['A1'] = dttm
ws['A1'].styles = s

<强>更新不再使用样式类，因为解决方案请参考此answer。

Answer 5

对于openpyxl 2.3.4，无法导入NumberFormat，但此代码用于设置样式：

from openpyxl.styles import Style

…
date_style = Style(number_format="DD/MM/YYYY HH:MM:MM")
ws['A1'].style = date_style

Answer 6

我发现这可行。尽管使用了number_format，但是它似乎可以识别放入excel wb中指定的日期格式。

import datetime
date = datetime.date(2020, 2, 24) # python datetime format is yyyy mm dd
ws.cell(row=[row_ref], column=[col_ref], value=date)
ws.cell(row=[row_ref], column=[col_ref]).number_format = 'dd/mm/yy'

Answer 7

from openpyxl import load_workbook
from openpyxl.styles import NamedStyle

xlsx_file = args.xlsx_file.name

# openning:
wb = load_workbook(filename = xlsx_file)


# create date style:
date_style = NamedStyle(name='date_style', number_format='DD.MM.YYYY HH:MM:MM')

# apply the style to the column H of the default sheet:
ws = wb.active
for row in ws[2:ws.max_row]:  # skip the header
    cell = row[7]             # column H
    cell.style = date_style

# saving:
wb.save(xlsx_file)

编辑：以上内容对我有效，但在我的同事计算机上不起作用。将单元格转换为固定的字符串：

import datetime

from openpyxl import load_workbook
from openpyxl.styles import Alignment

xlsx_file = 'file.xlsx'

date_format = '%Y-%b-%d'

# openning:
wb = load_workbook(filename = xlsx_file)

# we also center align that column:
alignment = Alignment(horizontal='center')

# apply python date format to column H of the default sheet, and convert the column to Excel text:
ws = wb.active
for row in ws[2:ws.max_row]:        # skip the header
    cell = row[7]   # column H
    if isinstance(cell.value, datetime.datetime):
        cell.value = cell.value.strftime(date_format)
        cell.alignment = alignment

# saving:
wb.save(xlsx_file)

同样包含在脚本中：

#!/usr/bin/env python3

import argparse
import datetime

from openpyxl import load_workbook
from openpyxl.styles import Alignment


# ==============
## parsing args:

desc="""

Applies python date format to a given column of the xlsx file (default sheet) and converts the column to a Excel text format.

Dependencies:
pip3 install --user --upgrade openpyxl
"""

parser = argparse.ArgumentParser(description=desc, formatter_class=argparse.RawDescriptionHelpFormatter)
parser.add_argument('--version', action='version', version='%(prog)s 0.01')

parser.add_argument('-f', '--file',
                    help = "xlsx file",
                    dest = 'xlsx_file',
                    type = argparse.FileType('r'),
                    )

parser.add_argument('-c', '--column',
                    help = "column (starting from A) (default to %(default)s)",
                    dest = 'column',
                    type = str,
                    default = "A",
                    )

parser.add_argument('-d', '--date-format',
                    help = "date format to use, e.g. %%d.%%m.%%Y (default to %(default)s)",
                    dest = 'date_format',
                    type = str,
                    default = '%Y-%b-%d',
                    )

args = parser.parse_args()


# =========
## program:

xlsx_file = args.xlsx_file.name

column_number = sum(
    [ ord(char) - 97 + i*26  for i,char in enumerate(
        list( args.column.lower() )
        ) ]
)

# openning:
wb = load_workbook(filename = xlsx_file)

# we also center align that column:
alignment = Alignment(horizontal='center')

# apply python date format to a given column of the default sheet, and convert the column to Excel text:
ws = wb.active
for row in ws[2:ws.max_row]:        # skip the header
    cell = row[column_number]
    if isinstance(cell.value, datetime.datetime):
        cell.value = cell.value.strftime(args.date_format)
        cell.alignment = alignment

# saving:
wb.save(xlsx_file)

如何使用格式的日期时间对象格式化单元格＆y; yyyy-mm-dd hh：mm：ss＆＃39;在Excel中使用openpyxl

修改

7 个答案: