Question

我有一份文件，其结构如下（简化）：

{
    "containers": [
    {
        "containerId": 1,
        "components": ["component1", "component2"]
    },
    {
        "containerId": 2,
        "components": ["component3", "component1"]
    }]
}

如何编写从BOTH容器中删除“component1”的查询？这可能吗？

到目前为止，我已尝试使用{"$pullAll": { "containers.$.component": ["component1"]}} $pull进行类似查询，设置multi: true，但我总是最终从第一个数组中删除该组件（我正在使用.update()）

编辑：未来的原始数据！

{
    "_id" : ObjectId("53a056cebe56154c99dc950b"),
    "_embedded" : {
        "click" : {
            "items" : [],
            "_links" : {
                "self" : {
                    "href" : "http://localhost/v1/click"
                }
            }
        },
        "container" : {
            "_links" : {
                "self" : {
                    "href" : "http://localhost/v1/container"
                }
            },
            "items" : [ 
                {
                    "name" : "Container test",
                    "uriName" : "Container_test",
                    "description" : "this is a test container",
                    "containerId" : "CONTAINER TEST+SITE_TEST",
                    "component" : [ 
                        "ANOTHER COMPONENT+SITE_TEST", 
                        "ANOTHER COMPONENT+SITE_TEST", 
                        "SARASA+SITE_TEST"
                    ],
                    "_links" : {
                        "self" : {
                            "href" : "http://localhost/v1/container/CONTAINER TEST+SITE_TEST"
                        }
                    }
                }, 
                {
                    "name" : "sasasa",
                    "uriName" : "sasasa",
                    "description" : "container description",
                    "containerId" : "SASASA+SITE_TEST",
                    "component" : [ 
                        "ANOTHER COMPONENT+SITE_TEST", 
                        "COMPONENT+SITE_TEST", 
                        "FAFAFA+SITE_TEST", 
                        "SARASA+SITE_TEST"
                    ],
                    "_links" : {
                        "self" : {
                            "href" : "/v1/container/SASASA+SITE_TEST"
                        }
                    }
                }
            ]
        }
    },
    "name" : "SITE_TEST",
    "siteId" : "SITE_TEST",
    "url" : "/v1/site"
}

好的，我正在尝试从两个容器中删除组件“SARASA + SITE_TEST”。我正在使用robomongo来测试查询。我已经尝试了db.site.update({"_embedded.container.items.component": "SARASA+SITE_TEST"},{"$pullAll": { "_embedded.container.items.component": ["SARASA+SITE_TEST"]}}, {multi: true})但它没有用，之前我已经尝试了db.site.update({"_embedded.container.items.component": "SARASA+SITE_TEST"},{"$pull": { "_embedded.container.items.$.component": "SARASA+SITE_TEST"}}, {"multi": true})，但它也没有用。我假设robomongo直接暴露了mongo驱动程序，我没有尝试从命令行运行它。

（该文档是“站点”，这就是为什么我的查询以db.site开头）

Answer 1

我遇到了类似的问题，我尝试了$ pullAll并且有效。

https://docs.mongodb.org/manual/reference/operator/update/pullAll/

Answer 2

我尝试了数据的简化版本和$ pull工作：

> db.testcoll.insert({"containers": {"containreId": 1, "components": ["component1", "component2"]}})
> db.testcoll.insert({"containers": {"containreId": 2, "components": ["component3", "component1"]}})
> db.testcoll.find()
{ "_id" : ObjectId("53a8428ca2696f063b5c51eb"), "containers" : { "containreId" : 1, "components" : [  "component1",  "component2" ] } }
{ "_id" : ObjectId("53a8429ea2696f063b5c51ec"), "containers" : { "containreId" : 2, "components" : [  "component3",  "component1" ] } }
> db.testcoll.update({"containers.components": "component1"}, {$pull: {"containers.components": "component1"}}, {multi: true})
> db.testcoll.find()
{ "_id" : ObjectId("53a8428ca2696f063b5c51eb"), "containers" : { "components" : [  "component2" ], "containreId" : 1 } }
{ "_id" : ObjectId("53a8429ea2696f063b5c51ec"), "containers" : { "components" : [  "component3" ], "containreId" : 2 } }

MongoDB从多个阵列更新$ pull文档

2 个答案: