Question

我想将任意数字输入数组b[]，数量为numCase次。

#include <iostream>
using namespace std;

//entry point

int main()

{


//Declarations

int b[20]; // array size 20 ( limit of inputs)
int c = 0;
int numCase;
int input;





 cout << "ENTER NUMBER OF CASES (MAXIMUM NUMBER OF 20):  \n";
 cin >> numCase;


//checks that numCase is less than or equal to (20) and does not exceed
if (numCase < 21)
        {



// gets input number based on the numCase

do
{


cout << "ENTER A NUMBER (MAXIMUM OF 5 DIGITS): \n";
                cin >> input;
                cout << "\n";
                b[c] = input;
                c++;



} while (c != numCase);


cout << b[c] ;  //  this is my problem it OUTPUTS RANDOM VALUE, 
     //but i can  see on my watch list that b has the values of my input.
}

}

Answer 1

您正在填充0 N的{{1}}条目，然后打印您尚未填写的条目b。

Answer 2

变量c应该初始化为零。

} while (c != numCase);

c = 0;

Answer 3

cout＆lt;＆lt; b [c]; //在此语句中c已经到达numCase，你没有分配任何值

Answer 4

如果要显示存储在数组b []中的所有数字然后你可以把你的代码写成

for(int i=0;i<=20;i++)
{ if(b[i]<101)   //This will exclude all the values which are greater than 101
   {cout<<"\n"<<b[i];}}

Answer 5

我认为这是你可能正在寻找的东西：

for (int i=0; i<numCase; i++)
{
    if(b[i] >= x) //x is a variable that u can set as a limit. eg. 700
    {
        cout<<"\n"<<b[i];
    }
}

希望有所帮助

为什么我的数组不存储任何输入值？

5 个答案: