QT python将传递参数连接到函数

时间:2014-06-23 07:01:26

标签: python qt user-interface pyside

为什么此代码有效:

from PySide.QtCore import *
from PySide.QtGui import *
import sys
from functools import partial

import pyside # my code generated by QT Design

class MainDialog(QMainWindow, pyside.Ui_MainWindow):

    def __init__(self, parent=None):
        super(MainDialog,self).__init__(parent)
        self.setupUi(self)


        self.connect(self.Connect_buttom, SIGNAL("clicked()"), partial(self.get_fb_token, "aaaaa","bbbbbb"))


    def get_fb_token(self,email,passwd): 
        print email
        print passwd


app = QApplication(sys.argv)
form = MainDialog()
form.show()
app.exec_()

并打印aaaaa和bbbbb

但如果我改变:

self.connect(self.Connect_buttom, SIGNAL("clicked()"), partial(self.get_fb_token, "aaaaa","bbbbbb"))

self.connect(self.Connect_buttom, SIGNAL("clicked()"), partial(self.get_fb_token, self.FB_username.text() ,self.FB_password.text()))

它不打印我在文本框FB_password和FB_username中引入的内容(它不会崩溃,但它不会打印任何内容,如果它不是将两个参数都发送到函数get_fb_token)??? / p>

**从http://www.blog.pythonlibrary.org/2013/04/10/pyside-connecting-multiple-widgets-to-the-same-slot/获取示例 我正在使用QT和pyside

1 个答案:

答案 0 :(得分:2)

定义连接时会创建partial对象,而不是在触发事件时创建。这意味着在连接时调用FB_username.text(),因此它将始终打印您在设计器中设置的内容。

要实现您想要的功能,您必须使用一个在调用时检索这些值的函数。 最简单的解决方案是:

from PySide.QtCore import *
from PySide.QtGui import *
import sys

import pyside # my code generated by QT Design

class MainDialog(QMainWindow, pyside.Ui_MainWindow):

    def __init__(self, parent=None):
        super(MainDialog,self).__init__(parent)
        self.setupUi(self)

        # use new-style signals & slots!
        self.Connect_buttom.clicked.connect(self.get_fb_token)

    def get_fb_token(self):
        email = self.FB_username.text()
        password = self.FB_password.text()

        print email
        print passwd


app = QApplication(sys.argv)
form = MainDialog()
form.show()
app.exec_()

如果出于某种原因,您不想修改get_fb_token,可以像这样使用lambda

self.Connect_buttom.clicked.connect(lambda: self.get_fb_token(self.FB_username.text(), self.FB_password.text()))