Question

我使用PHP根据结果集更新项目表。

while (!$rs->EOF) { 
    $conn->Execute("UPDATE [table] SET qty='".$quantity."' WHERE 
            locn ='".$locn."' AND pdln ='".$pdln."'");

    echo "Item updated...<br/>";  /////////Message display here

    $rs->MoveNext();                
}

由于数据量非常大，我希望在每次成功更新一行后，向用户显示一条消息。有没有办法使用Ajax或Jquery来实现这个目标？

Answer 1

if (ob_get_level() == 0) ob_start();

while (!$rs->EOF) { 
$conn->Execute("UPDATE [table] SET qty='".$quantity."' WHERE 
     locn ='".$locn."' AND pdln ='".$pdln."'");
    echo "Item updated...<br/>";  /////////Message display here
        ob_flush();
        flush();
        sleep(1);

    $rs->MoveNext();                
} 
echo "Done.";
ob_end_flush();

Answer 2

基于我的理解

while (!$rs->EOF) { 
    $conn->Execute("UPDATE [table] SET qty='".$quantity."' WHERE 
            locn ='".$locn."' AND pdln ='".$pdln."'");

    echo TRUE;  // You can return False if row didn't update if you want

    $rs->MoveNext();                
}

在HTML中，使用jQuery函数.ajax()或使用Javascript。

   $.ajax
   ({
    url: "<?php echo site_url();?>/site/bookmark/"+$bookmark_button.parent().attr('id'),
    type: "GET",
    success: function(data)
    {

      switch ( data )
      {
        case TRUE:
           console.log('Item updated successfully '); // Change the way it's displayed as you like
          break;
        case FALSE:
           console.log('Item did not update successfully '); // Change the way it's displayed as you like
        break;
      }

    },
    error: function(data)
    {
      console.log('Error updating item, connection error maybe?'); // Optional
    }
  });

每次SQL更新成功时显示消息

2 个答案: