Question

我正在使用WAMP服务器并在其上创建了一个数据库和一个表。所有名称都是正确的，用户可以完全访问所有内容。当我运行代码时，它会输出＆＃34;无法选择数据库＆＃34;。感谢。

<?php

if(isset($_POST["Submit"])){  
        print_r ($_POST["nutrient"]);
}




session_start();

//establish connection
$server = "localhost";
$db_username = "root";
$db_password = "";
$database = "gainlife_cavin";
$table = "cavintable"; 


//connect PHP script to database
$connection = mysqli_connect($server, $db_username, $db_password, $database);


//select database to use
@mysql_select_db($database) or die( "Unable to select database");

//$query = "INSERT INTO $table VALUES("")"
//mysql_query($query)

mysql_close();



?>

<body>
</form>

Answer 1

尝试以下内容。

<?php
//establish connection
$server = "localhost";
$db_username = "root";
$db_password = "";
$database = "gainlife_cavin";
$table = "cavintable"; 

    //connect PHP script to database
    $connection =mysqli_connect("$server","$db_username","$db_password","$database");

    if (mysqli_connect_errno())
      {
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
      }

    //Your query here

    mysqli_close($connection);
?>

Answer 2

我使用简单的代码1行。这是我正在使用的代码。

$conn = mysqli_connect($db_host, $db_user, $db_pass, $db_name);
// Evaluate the connection
if (mysqli_connect_errno()) {
echo mysqli_connect_error();
exit();
}

Answer 3

你从MySQLI到选择数据库以及你的其余代码都没有使用MySQLI。

Answer 4

试试这个。我已将mysqli_connect更改为mysql_connect和mysql_select_db变量。

//connect PHP script to database
$connection = mysql_connect($server, $db_username, $db_password, $database);


//select database to use
$select  = mysql_select_db($connection) or die( "Unable to select database");

为什么这个PHP代码不允许我连接到我的数据库？

4 个答案: