Question

我有这样的文件：

{   "baths": 2,   "beds": 3,   "id": "3225C",   "addrs": [
    {
      "line2": "",
      "line3": "",
      "state": "OH",
      "zip": "67845",
      "line1": "3225 ABC AVE",
      "city": "CLEVELAND"
    },
    {
      "line2": "",
      "line3": "",
      "state": "FL",
      "zip": "32818",
      "line1": "2438 DEF AVE",
      "city": "ORLANDO"
    }   ],   "homeAddress": {
    "line2": "",
    "line3": "",
    "state": "FL",
    "zip": "32818",
    "line1": "1234 CHICOTA AVE",
    "city": "ORLANDO"   },   "rentingAddresses": {
    "ownsObjects": true,
    "count": 0,
    "arrayManager": {},
    "items": []   },   "mailAddress": [
    "4561 RAYCO AVE",
    "",
    "",
    "ORLANDO",
    "FL",
    "32818"   ] }

我试图找到哪个客户有一个addrs，其中州是＆＃34; OH＆＃34;。我的aql查询是：

for client in clients.addrs
filter client.state == "OH"
return client

但我一直在[1563] list expected。有没有其他方法可以使用数组？

Answer 1

你可以这样做：

FOR client IN clients
   FILTER 'OH' IN client.addrs[*].state
   RETURN client

这应该返回所有至少有一个元素的客户端＆＃34; addrs的＆＃34;属性为＆＃34; state＆＃34; ==＆＃34; OH＆＃34;

Answer 2

首先，您必须使用以下过滤器选择该集合中的文档：

FOR doc IN clients
 FILTER doc.id == "3225C"
   FOR d IN doc.addrs
    FILTER d.state == "OH"
   RETURN d

这将返回状态==“OH”的addrs对象。如果您想获得完整的文档，只需将RETURN d替换为RETURN doc。

过滤ArangoDB中的数组值

2 个答案: