Question

您好我创建了一个ANDROID应用程序，它将订单发送到网络服务器并将它们传递给数据库。

虽然在我的应用程序中我多次使用asynctask将json值传递给php文件，但现在我已经堆叠了两天。

我所做的是创建json值并调用URL将值传递给PHP文件。

下面是我发送json的'doInBackground'函数：

  //I PASS THE json object which look like:
   {
   "app_id":"5",
    "items":[{"orderItemPrice":5,"orderPrID":59,"orderItems":1}],
   "serial":"cb734fea0c0d40e65",
   "orderDate":"2014-06-22 09:41:21",
   "orderComment":"my comment",
   "orderCoupon":"1111"
    }
  ///
  protected Boolean doInBackground(JSONObject... obj) {



        SchemeRegistry supportedSchemes = new SchemeRegistry();
        SocketFactory sf = PlainSocketFactory.getSocketFactory();
        supportedSchemes.register(new Scheme("http", sf, 80));

        HttpParams params = new BasicHttpParams();
        HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
        HttpProtocolParams.setContentCharset(params, "UTF-8");
        HttpProtocolParams.setUseExpectContinue(params, true);

        ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, supportedSchemes);
        DefaultHttpClient httpclient = new DefaultHttpClient(ccm, params);


        try{
            HttpPost httppost = new HttpPost(AppConstants.URL_SUBMIT_ORDERS);
            httppost.setHeader("Content-type", "application/json");

            StringEntity se = new StringEntity(obj.toString());
            se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
            httppost.setEntity(se);

            HttpResponse response = httpclient.execute(httppost);
            String temp = EntityUtils.toString(response.getEntity());

    //THE RETURNED VALUE IS A MYSQL ERROR "COLUMN ID CANNOT BE NULL"
     Log.i("tag", temp);
            return true;
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch(Throwable t){ //new line at 07/04/2014
            t.printStackTrace();// new line
        }
        return false;
    }

WebServer上的php文件是：

  <?php
   **#db info**
define("HOST", "xxxx");    
define("USER", "xxx");   
define("PASSWORD", "xxx");  
define("DATABASE", "xxx");  

define("CAN_REGISTER", "any");
define("DEFAULT_ROLE", "member");

define("SECURE", FALSE);   

**#read data from client**
$fp = fopen('php://input','r');
$rawData = stream_get_contents($fp);

function getRandomWord($len = 9) {
    $word = array_merge( range('A', 'Z'));
    shuffle($word);
    return substr(implode($word), 0, $len);
}

#CREATE ORDER NUMBER
$orderNumber = getRandomWord();

try{

    $arr = json_decode($rawData,true);//convert it to array

    $arrCount = count($arr['items']); 

        #DB connection
        $DBH = new PDO("mysql:host=xxxx;dbname=xxx",USER,PASSWORD);
        $DBH->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION);

        #step 1         
        #insert MAIN ORDER  
        $STH = $DBH->prepare("INSERT INTO tbl_orders (`orderfk_appID`,`orderfk_userSerial`,`orderNumber`,`orderCoupon`,`orderComment`,`orderDate`) values (:app_id,:serial,:orderNumber,:orderCoupon,:orderComment,:orderDate)");

        $STH->bindParam(':app_id',$arr['app_id']);
        $STH->bindParam(':serial',$arr['serial']);
        $STH->bindParam(':orderNumber',$orderNumber);
        $STH->bindParam(':orderCoupon',$arr['orderCoupon']);
        $STH->bindParam(':orderComment',$arr['orderComment']);
        $STH->bindParam(':orderDate',$arr['orderDate']);

        #execute
        $STH->execute();
        $LastOrderId = $DBH->lastInsertId();


        $DBH = null; //close the connection

        #return result to the client
        echo json_encode(array("Orders"=>$LastOrderId));
    }
catch(PDOException $e){
    echo "error: ".$e->getMessage();
    file_put_contents('PDOErrors.txt', $e->getMessage()."<br/><br/>", FILE_APPEND);
    }

＆GT;

它接缝不会将json值传递给PHP文件，因为每当我尝试使用print_r（$ arr）显示数组时;或echo json_encode（array（“Orders”=＆gt; $ arr））;我得到了空。

请有人帮助我并提及我没有看到的错误。谢谢。

Android应用程序将json值发送到php，但我无法接收它们

0 个答案: