Question

我们在以下代码中遇到此错误。我是这方面的初学者，所以请以简单的方式解释我们可能做错了什么。

#include <Servo.h>

Servo myservo1;  // create servo object to control a servo 
Servo myservo2; 
Servo myservo3;
Servo myservo4;
Servo myservo5; 

int potpin1 = 0;  // analog pin used to connect the potentiometer
int val1;    // variable to read the value from the analog pin 

int potpin2 = 1;
int val2;  

int potpin3 = 2;
int val3;

int potpin4 = 3; 
int val4;

int potpin5 = 4;
int val5;

void setup() 
{
  myservo1.attach(3);  // attaches the servo on pin 9 to the servo object
  myservo2.attach(5);
  myservo3.attach(6);
  myservo4.attach(9);
  myservo5.attach(10);
} 

void loop()
{ 
  val1 = analogRead(potpin1);            // reads the value of the potentiometer (value between 0 and 1023) 
  val1 = map(val1, 0, 1023, 0, 179);     // scale it to use it with the servo (value between 0 and 180)
  myservo1.write(val1);                  // sets the servo position according to the scaled value 

  delay(15);                           // waits for the servo to get there 

  val2 = analogRead(potpin2);
  val2 = map(val2, 0, 1023, 0, 179);
  myservo2.write(val2);

  delay(15);           

  val3 = analogRead(potpin3); 
  val3 = map(val3, 0, 1023, 0, 179); 
  myservo3.write(val3);

  delay(15);           

  val4 = analogRead(potpin4);  
  val4 = map(val4, 0, 1023, 0, 179);
  myservo4.write(val4);

  delay(15);           

  val5 = analogRead(potpin5);
  val5 = map(val5, 0, 1023, 0, 179); 
  myservo5.write(val5); 

  delay(15);           
}

Answer 1

该代码在最新的Arduino IDE（在OSX上）编译得很好。您没有说明您所使用的平台或用于编译代码的方式。听起来你要么安装了Arduino IDE和libs，要么正在使用其他设置不正确的东西。

错误：在arduino uno中'typedef'之前的预期构造函数，析构函数或类型转换

1 个答案: