Question

我有一个数组。现在我想使用这个数组值在我的表中插入数据。 $claw是数组

Array
(
    [0] => Array
        (
            [0] => Alabama
            [1] => Yes
            [2] => R
            [3] => 

are free to enact restrictions greater than .

            [4] => 
            [5] => 
            [6] => 
            [7] => 

It is unlawful to sell
        )
)

现在我想使用此数组值在表中插入数据。

我正在使用此代码但无法正常工作

    public function Insert($claw)
    {


                $fields = array();
                for($i=0;$i<$claw; $i++) 
                {
                    for($j=0;$j<$claw[$i]; $j++) 
                    {               
                        $fields[] = $claw[$i][$j];
                    }
                }

                $sql = "Insert into information values(" . implode(', ', $fields) . ')';

return $this->MyCommandR($sql);


    }

我无法理解我的错误

Answer 1

您需要定义字段以保存这些数据 $ sql =“插入信息（name，yes，ABC，CBA）值（”。implode（'，'，$ fields）。'）';

或

$field = $conn->query("DESCRIBE  `".$table."`"); 
$constrantsQueryfield = array();
$constrantsQueryvalue = array();
while($row = mysqli_fetch_assoc($field))
{

if ($row['Field']!='ID' && $row['Key']!='PRI')
{
if (array_key_exists($row['Field'],$data))
{
if ($row['Key']=='DATE')
{
    $constrantsQueryfield[] = $row['Field'];
$constrantsQueryvalue[] = date("Y-m-d");
}
else
{
$constrantsQueryfield[] = $row['Field'];
$constrantsQueryvalue[] = $data[$row['Field']];
}
}
}
}
$constrantQuery = "INSERT INTO `".$table."` ";
for ($i = 0;$i<count($constrantsQueryfield);$i++)
{
if ($i == 0){
$constrantQuery .= "(";
}
$constrantQuery .= "`".$constrantsQueryfield[$i]."`";
if ($i+1 == count($constrantsQueryfield))
{
$constrantQuery .= ")";

}
else
{
    $constrantQuery .= ", ";

    }
}
$constrantQuery .= "  VALUES  ";
$contstantQuery .= "(" . implode(', ', $data) . ')'; // ANy data array

$conn->query($constrantQuery);

php mysql从数组中插入值

1 个答案: