Question

如果该节点的内容与另一个节点（兄弟节点）匹配，我试图显示节点的文本内容。这是XML：

<MemberId>
    <BillingInfo>
        <Details>
            <Line NUMBER="0">
                <ChargeDate>20140605</ChargeDate>
                <DueDate>20140605</DueDate>
                <TrackingNumber>PR DED</TrackingNumber>
                <Description>Account payroll deduction</Description>
                <RevCode>SJ1550</RevCode>
                <RevDesc>ACCOUNT PAYROLL DEDUCTION</RevDesc>
                <SalesAmount>-11.77</SalesAmount>
                <ServiceCharge>0.00</ServiceCharge>
                <GST>0.00</GST>
                <PST>0.00</PST>
                <Othertaxes>0.00</Othertaxes>
                <Total>-11.77</Total>
                <ChitCode>PR DED</ChitCode>
                <ChitDate>20140605</ChitDate>
            </Line>

            <Line NUMBER="1">
                <ChargeDate>20140605</ChargeDate>
                <DueDate>20140605</DueDate>
                <TrackingNumber>03128862</TrackingNumber>
                <Description>Mountain Mkt Sales</Description>
                <RevCode>SJ1553</RevCode>
                <RevDesc>MOUNTAIN MKT SALES</RevDesc>
                <SalesAmount>8.99</SalesAmount>
                <ServiceCharge>0.00</ServiceCharge>
                <GST>0.00</GST>
                <PST>0.61</PST>
                <Othertaxes>0.00</Othertaxes>
                <Total>9.60</Total>
                <ChitCode>03128862</ChitCode>
                <ChitDate>20140605</ChitDate>
            </Line>
        </Details>
    </BillingInfo>
    <Chits>
    <Chit>
    <Code>03128862</Code>
    <Body><![CDATA[
        Member#: 0ECHER
        Name: *******
        Area:  *********
        Server: JEANNEANE
        Chit#: 03128862
        Date:  June 5 2014
        ------- ------- ------- ------- -------
        1       MINGUA BEEF JER            8.99
        ------- ------- ------- ------- -------
        Sub-Total                          8.99


        TAX                                0.61
        ------- ------- ------- ------- -------
        Chit Total                         9.60



        MEMBER CHARGE                     -9.60
    ]]></Body>
    </Chit>
    </Chits>
</MemberId>

我成功显示了每个ChitCode和ChitDate，因为它们位于Line [@number]节点中。我想显示包含文本＆＃34; Chit＃：XXXXXX＆＃34;的Body节点。其中xxxxxx与Line-＆gt; ChitCode匹配。这是我的php，它显示Body，但它显示所有行项目的第一个Body：

<?php 
    foreach($Chitquery as $Chit) 
    {
        foreach($Linequery as $Line)
        {
            echo "<label class='collapse' for='".$Line->ChitCode."-".$Line->ChitDate."'>".$Line->Description."</label>
            <input id='".$Line->ChitCode."-".$Line->ChitDate."' type='checkbox'>
            <div>"; 
            // Creates hide - show link for each Description item
            // Start getting the matching Chit Code from Chit/Body                          

            if ($Chit->Code = $Line->ChitCode)
            {
                echo $Chit->Body."</div>";
            }
            else
            {
                echo " ".$Line->ChitCode."</div>";
            } // End If
        } //End  foreach Linequery
    } // End foreach Chitquery
?>

它是echo $ Chit-＆gt; Body。＆＃34;＆＃34 ;;我需要帮助，我想显示包含$ Line-＆gt; ChitCode值的Body。

哦，是的，由于“foreach”的不当放置，这些线条重复得很奇怪。声明！ screenshot of lists 救命！提前谢谢！

更新：我已经改变了我的PHP代码，现在我有隐藏显示div工作，没有重复，但我得到了＃array;＃39;而不是$ ChitBody。我无法弄清楚如何在$ ChitBody = $ member-＆gt; xpath中找到包含$ Line-＆gt; ChitCode的Body节点（＆＃39; Chits / Chit / Body [text（）=＆＃34;＆＃ 39;。$ Line-＆gt; ChitCode。＆＃39;＆＃34;]＆＃39;）;

<?php 
                        foreach($Linequery as $Line) { 
                        $ChitCode = $member->Chits->Chit->Code;
                        $ChitBody = $member->xpath('Chits/Chit/Body[text()="'.$Line->ChitCode.'"] ');
                        echo "<label class='collapse' for='".$Line->ChitCode."-".$Line->ChitDate."'>".$Line->Description."</label>
                         <input id='".$Line->ChitCode."-".$Line->ChitDate."' type='checkbox'>"; // Creates hide - show link for each Description item
                        // Start getting the matching Chit Code from Chit/Body                          
                            if ($ChitCode = $Line->ChitCode) {
                            echo "<div>Code: ".$ChitCode."<br>".$ChitBody."</div>";
                            } else {
                            echo "<div>".$Line->ChitCode."</div>";
                            } // End If
                        } //End  foreachLinequery
                     ?>

enter image description here

Answer 1

您很可能正在寻找xpath来查询您的文档。

例如迭代线 - 我不完全理解你为什么这样做，但是这是我理解它的方式（仅文本输出）：

$xml = simplexml_load_string($buffer);

foreach ($xml->xpath('//Details/Line') as $line)
{
    printf("#%d: %s\n", $line['NUMBER'], $line->Description);            
}

给出：

#0: Account payroll deduction
#1: Mountain Mkt Sales

我猜你看到这一般是如何运作的。所以现在根据$line->ChitCode获取chit，我认为实际上对你来说更有趣。它还更好地说明了xpath的好处：

foreach ($xml->xpath('//Details/Line') as $line)
{
    printf("#%d: [%s] %s\n", $line['NUMBER'], $line->ChitCode, $line->Description);

    $query  = sprintf("//Chits/Chit[Code = '%s']/Body", $line->ChitCode);
    $result = $xml->xpath($query);

    if ($result) {
        $chit = $result[0];
        echo $chit;
    } else {
        echo ' -- no chit found -- ';
    }
    echo "\n";
}

这次查询包含查找数字的条件（如果要进行此保存，escape the string properly（more info）），它基本上会创建以下两个xpath查询：

//Chits/Chit[Code = 'PR DED']/Body

//Chits/Chit[Code = '03128862']/Body

我再次猜你可以想象那些意味着什么。如果找到这样的<Body>元素，则上面的代码输出它。这就是结果的样子：

#0: [PR DED] Account payroll deduction
 -- no chit found -- 
#1: [03128862] Mountain Mkt Sales

        Member#: 0ECHER
        Name: *******
        Area:  *********
        Server: JEANNEANE
        Chit#: 03128862
        Date:  June 5 2014
        ------- ------- ------- ------- -------
        1       MINGUA BEEF JER            8.99
        ------- ------- ------- ------- -------
        Sub-Total                          8.99


        TAX                                0.61
        ------- ------- ------- ------- -------
        Chit Total                         9.60



        MEMBER CHARGE                     -9.60

我希望这能让你有足够的洞察力来开始它。 xpath() is just a method on SimpleXMLElement因此你可以将这个与我没有复制的代码结合起来，只是为了让示例更小（我在这里使用纯文本输出的原因相同，将与HTMl同样工作，但会使示例膨胀）。

OP增加：

工作量很棒!!

我将您的代码改编为此代码，并且完美运行：

foreach ($Linequery as $Line) {
    $LineChitCode = $Line->ChitCode;
    $ChitBody     = sprintf("//Chits/Chit[Code = '%s']/Body", $LineChitCode);
    $CBresult     = $member->xpath($ChitBody);
    echo "<label class='collapse' for='" . $Line->ChitCode . "-" . $Line->ChitDate . "'>" . $Line->Description . "</label>
                             <input id='" . $Line->ChitCode . "-" . $Line->ChitDate . "' type='checkbox'>"; // Creates hide - show link for each Description item
    // Start getting the matching Chit Code from Chit/Body                            
    if ($CBresult) {
        $chit = $CBresult[0];
        echo "<div>Code: " . $LineChitCode . "<br>" . $chit . "</div>";
    } else {
        echo "<div>" . $Line->ChitCode . "</div>";
    }
}

谢谢你，你在3天的时间里救了我，想要解决这个问题!!

Answer 2

你可以使用if（$ Chit-＆gt; Code == $ Line-＆gt; ChitCode）而不是if（$ Chit-＆gt; Code = $ Line-＆gt; ChitCode）

SimpleXML和php - 获取包含与另一个节点匹配的文本的节点

2 个答案: