Question

我正在尝试做问题所说的。（可能令人困惑）这里有一些代码可以让你理解我正在尝试做的事情。

classes = new string[14, 5];
classes[0] = {"Value1 [0, 0]", "Value2 [0, 1]", "Value3 [0, 2]", "Value4 [0, 3]", "Value5 [0, 4]"};

Answer 1

某些语言或环境（如Matlab）允许这样的操作，但C＃不能为矩形数组String [x，y]提供此类访问。

使用此类数组，您应该单独更改每个元素：

String[,] classes = new string[14, 5];classes = new string[14, 5];

Int32 rowToChange = 0;

for(Int32 col = 0; col < classes.GetLength(1); col++)
{
   classes[rowToChange, col] = String.Format("Value{0} [{1}. {0}]", rowToChange , col  );
}

但你可以使用锯齿状数组：String [] []

String[][] classes = new string[14][];

Int32 rowToChange = 0;

classes[rowToChange] = new String[]{"Value1 [0, 0]", "Value2 [0, 1]", "Value3 [0, 2]", "Value4 [0, 3]", "Value5 [0, 4]"};

您可以阅读What are the differences between a multidimensional array and an array of arrays in C#?以了解差异

插入2D数组第1列的所有第2列的值

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