Question

我想从Mozilla，Internet Explorer和Chrome调用Web服务。

Bellow是我的 LaboratoryService.js 文件，它调用Web服务：

function StringBuffer() {
    this.__strings__ = new Array;
}

StringBuffer.prototype.append = function (str) {
    this.__strings__.push(str);
};

StringBuffer.prototype.toString = function () {
    return this.__strings__.join("");
};

function LaboratoryService() {
    this.url = "http://25.48.190.93:8082/labratory?wsdl";
}

LaboratoryService.prototype.buildRequest = function () {
    var oBuffer = new StringBuffer();

    oBuffer.append("<soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\" ");
    oBuffer.append("xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" ");
    oBuffer.append("xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">");
    oBuffer.append("<soap:Body>");
    oBuffer.append("<getLabratory xmlns=\"http://nano.ito.ir/\" />");
    oBuffer.append("</soap:Body>");
    oBuffer.append("</soap:Envelope>");

    return oBuffer.toString();
};

LaboratoryService.prototype.send = function () {
    var oRequest = new XMLHttpRequest;
    oRequest.open("post", this.url, false);
    oRequest.setRequestHeader("Content-Type", "text/xml");
    oRequest.setRequestHeader("SOAPAction", this.action);
    oRequest.send(this.buildRequest());
    if (oRequest.status == 200) {
        return this.handleResponse(oRequest.responseText);
    } else {
        throw new Error("Request did not complete, code " + oRequest.status);
    }
};

LaboratoryService.prototype.handleResponse = function (sResponse) {
    var start = sResponse.indexOf('div') - 4;
    var end = sResponse.lastIndexOf('div') + 7;

    return sResponse.substring(start, end);
};

Bellow是我的HTML代码，它使用 LaboratoryService.js 来显示数据：

<html xmlns="http://www.w3.org/1999/xhtml">

<head>
    <title>Get Labratories</title>
    <script language="JavaScript" src="LaboratoryService.js"></script>
    <script language="JavaScript" src="jquery-1.8.0.min.js"></script>

    <script language="JavaScript" type="text/javascript">
        $(document).ready(function () {
            $("#btnGetLaboratories").click(function () {
                var oService = new LaboratoryService();
                var fResult = oService.send();
                var newData = $('<div/>').html(fResult).text();

                $("#divResult").html(newData);
            });
        });
    </script>
</head>

<body>
    <input id="btnGetLaboratories" type="button" value="Get Laboratories" />
    <div id="divResult">

    </div>
</body>

</html>

这种方法在Internet Explorer中运行良好问题是这种方法在FireFox和Chrome中不起作用我认为oRequest.send(this.buildRequest());在FireFox和Chrome中不起作用。

使用JQuery编辑Web服务调用

我更改 LaboratoryService.prototype.send 以使用JQuery调用Web Service，如下所示：

LaboratoryService.prototype.send = function () {
    $.ajax({
        type: "POST",
        url: this.URL,
        contentType: "text/xml",
        headers: { "SOAPAction": this.action },
        success: function (msg) {
            return this.handleResponse(msg);
        },
        error: function (e) {
            alert('error');
        }
    });
};

但它提醒error。如何使用JQuery调用Web Service？

再次编辑代码

我改变了我的JQuery AJAX调用。它在Internet Explorer中正常工作，但在Chrome和Firefox中返回error。

LaboratoryService.prototype.send = function () {
    $.ajax({
        type: "POST",
        url: this.URL,
        contentType: "text/xml; charset=\"utf-8\"",
        dataType: "xml",
        data: this.buildRequest(),
        processData: false,
        success: function processSuccess(data, status, req) {
            if (status == "success") {
                var sResponse = req.responseText;
                var start = sResponse.indexOf('div') - 4;
                var end = sResponse.lastIndexOf('div') + 7;

                var newData = $('<div/>').html(sResponse.substring(start, end)).text();

                $("#divResult").html(newData);
            }
        },
        error: function () {
            alert('error');
        }
    });
};

Answer 1

只需改变：

LaboratoryService.prototype.send = function () {
    var oRequest = new XMLHttpRequest;
    oRequest.open("post", this.url, true);  
    oRequest.setRequestHeader('User-Agent','XMLHTTP/1.0');

    oRequest.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
    oRequest.setRequestHeader("SOAPAction", this.action);
    oRequest.send(this.buildRequest());
    if (oRequest.status == 200) {
        return this.handleResponse(oRequest.responseText);
    } else {
        throw new Error("Request did not complete, code " + oRequest.status);
    }
};

请refer this link.

如何以跨浏览器方式调用Web服务

1 个答案: