Question

在以下两个sql查询sql1中未选择任何行，sql2仅为111@k2.com选择1

 var ids="'111@k2.com','222@k2.com','333@k2.com','444@k2.com','555@k2.com','666@k2.com'"

    val sql1 = SQL("SELECT id,point,privacy FROM `pointTable` WHERE state=1 and  id in ({users})").on("users" -> ids)
    sql1().map { row =>
      val point = if (row[Boolean]("privacy")) { row[Double]("point").toString } else { "0" }
      println(write(Map("id" -> row[String]("id"), "point" -> point)))
    }

    val sql2 = SQL("SELECT id,point,privacy FROM `pointTable` WHERE state=1 and  id in (" + ids + ")")
    sql2().map { row =>
      val point = if (row[Boolean]("privacy")) { row[Double]("point").toString } else { "0" }
      println(write(Map("id" -> row[String]("id"), "point" -> point)))
    }

在phpmyadmin中，当我运行此查询时，它会返回6行，然后为什么不能在这里完美运行。我正在使用Play框架2.2与scala 2.1

Answer 1

那不行。传递users虽然on将转义整个字符串，因此它将显示为一个值而不是列表。 Play 2.3中的Anorm实际上允许您将列表作为参数传递，但在这里您必须解决这个问题。

val ids: List[String] =  List("111@k2.com", "222@k2.com", "333@k2.com")
val indexedIds: List[(String, Int)] = ids.zipWithIndex

// Create a bunch of parameter tokens for the IN clause.. {id_0}, {id_1}, ..
val tokens: String = indexedIds.map{ case (id, index) => s"{id_${index}}" }.mkString(", ")

// Create the parameter bindings for the tokens
val parameters = indexedIds.map{ case (id, index) => (s"id_${index}" -> toParameterValue(id)) }

val sql1 = SQL(s"SELECT id,point,privacy FROM `pointTable` WHERE state=1 and  id in (${tokens})")
    .on(parameters: _ *)

在playframework中的mysql查询子句

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