Question

我想要不是通过asc或desc对列进行排序，但是我希望它根据我设置的顺序进行排序。例如，我有这些数据：

Varchar1 |  Varchar2 | Value | Something
1401_1   | 1401_1_9  | 1     | Something1
1401_1   | 1401_1_9  | 0     | Something2
1401_1   | 1401_1_11 | 1     | Something1
1401_1   | 1401_1_11 | 1     | Something2
1401_1   | 1401_1_13 | 0     | Something1
1401_1   | 1401_1_13 | 1     | Something2
1401_1   | 1401_1_15 | 0     | Something1
1401_1   | 1401_1_15 | 1     | Something2
1401_1   | 1401_1_17 | 1     | Something1
1401_1   | 1401_1_17 | 0     | Something2
1401_1   | 1401_1_19 | 1     | Something1
1401_1   | 1401_1_19 | 0     | Something2
1401_1   | 1401_1_21 | 1     | Something1
1401_1   | 1401_1_21 | 1     | Something2
1401_1   | 1401_1_23 | 0     | Something1
1401_1   | 1401_1_23 | 1     | Something2
1401_1   | 1401_1_1  | 0     | Something1
1401_1   | 1401_1_1  | 1     | Something2
1401_1   | 1401_1_3  | 1     | Something1
1401_1   | 1401_1_3  | 0     | Something2
1401_1   | 1401_1_5  | 1     | Something1
1401_1   | 1401_1_5  | 0     | Something2
1401_1   | 1401_1_7  | 1     | Something1
1401_1   | 1401_1_7  | 1     | Something2

这是我的代码：

SELECT * 
FROM (SELECT TOP 12 
            [varchar2] AS [T2], 
            SUM(CASE WHEN [Type] = 'something1' THEN value END) AS something1, 
            SUM(CASE WHEN [Type] = 'something2' THEN value END) AS [something2] 
    FROM tbl_table 
    GROUP by [varchar2] 
    ORDER by [varchar2] DESC)x 
ORDER BY [T2] ASC

该代码产生如下内容：1401_1_1,1401_1_11,1401_1_13,1401_1_15,1401_1_17， 1401_1_19,1401_1_21,1401_1_23,1401_1_3,1401_1_5,1401_1_7,1401_1_9 ==＆gt;它在varchar中排序

我希望它按照以下顺序排序：1401_1_9,1401_1_11,1401_113,1401_1_15,1401_117,1401_1_19,1401_1_21,1401_1_23,1401_1_1,1401_1_3,1401_1_5,1401_1_7

有可能吗？

Answer 1

您可以使用以下代码：

Order by PARSENAME(REPLACE(@varchar2,'_','.'),3),
         PARSENAME(REPLACE(@varchar2,'_','.'),2),
         CASE WHEN PARSENAME(REPLACE([varchar2],'_','.'),1)>=9 THEN 1 ELSE 2 END,
         PARSENAME(REPLACE(@varchar2,'_','.'),1)

如何在sql中使用自定义排序顺序

1 个答案: