所以，这个程序只是让用户输入一个字符串，并计算每个字符的出现次数，然后显示最频繁。
我输入＆＃34; AABBCCC＆＃34;，它告诉我最大值为7，最常见的是＆＃34; Q＆＃34;。
countList = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 \
, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 \
, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 \
, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 \
, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
index = 0
for character in userInput:
if character == "Q" or "q":
countList[0] += 1
elif character == "W" or "w":
countList[1] += 1
elif character == "E" or "e":
countList[2] += 1
elif character == "R" or "r":
countList[3] += 1
elif character == "T" or "t":
countList[4] += 1
elif character == "Y" or "y":
countList[5] += 1
elif character == "U" or "u":
countList[6] += 1
elif character == "I" or "i":
countList[7] += 1
elif character == "O" or "o":
countList[8] += 1
elif character == "P" or "p":
countList[9] += 1
elif character == "A" or "a":
countList[10] += 1
elif character == "S" or "s":
countList[11] += 1
elif character == "D" or "d":
countList[12] += 1
elif character == "F" or "f":
countList[13] += 1
elif character == "G" or "g":
countList[14] += 1
elif character == "H" or "h":
countList[15] += 1
elif character == "J" or "j":
countList[16] += 1
elif character == "K" or "k":
countList[17] += 1
elif character == "L" or "l":
countList[18] += 1
elif character == "Z" or "z":
countList[19] += 1
elif character == "X" or "x":
countList[20] += 1
elif character == "C" or "c":
countList[21] += 1
elif character == "V" or "v":
countList[22] += 1
elif character == "B" or "b":
countList[23] += 1
elif character == "N" or "n":
countList[24] += 1
elif character == "M" or "m":
countList[25] += 1
elif character == "`":
countList[26] += 1
elif character == "~":
countList[27] += 1
elif character == "1":
countList[28] += 1
elif character == "!":
countList[29] += 1
elif character == "2":
countList[30] += 1
elif character == "@":
countList[31] += 1
elif character == "3":
countList[32] += 1
elif character == "#":
countList[33] += 1
elif character == "4":
countList[34] += 1
elif character == "$":
countList[35] += 1
elif character == "5":
countList[36] += 1
elif character == "%":
countList[37] += 1
elif character == "6":
countList[38] += 1
elif character == "^":
countList[39] += 1
elif character == "7":
countList[40] += 1
elif character == "&":
countList[41] += 1
elif character == "8":
countList[42] += 1
elif character == "*":
countList[43] += 1
elif character == "9":
countList[44] += 1
elif character == "(":
countList[45] += 1
elif character == "0":
countList[46] += 1
elif character == ")":
countList[47] += 1
elif character == "-":
countList[48] += 1
elif character == "_":
countList[49] += 1
elif character == "=":
countList[50] += 1
elif character == "+":
countList[51] += 1
elif character == "[":
countList[52] += 1
elif character == "{":
countList[53] += 1
elif character == "]":
countList[54] += 1
elif character == "}":
countList[55] += 1
elif character == "\\":
countList[56] += 1
elif character == "|":
countList[57] += 1
elif character == ";":
countList[58] += 1
elif character == ":":
countList[59] += 1
elif character == "'":
countList[60] += 1
elif character == "\"":
countList[61] += 1
elif character == ",":
countList[62] += 1
elif character == "<":
countList[63] += 1
elif character == ".":
countList[64] += 1
elif character == ">":
countList[65] += 1
elif character == "/":
countList[66] += 1
elif character == "?":
countList[67] += 1
mostFrequent = max(countList)
print(mostFrequent)
characterKey = ["Q", "W", "E", "R", "T", "Y", "U", "I", "O", "P", "A" \
, "S", "D", "F", "G", "H", "J", "K", "L", "Z", "X", "C", "V", "B", "N", "M" \
, "`", "~", "1", "!", "2", "@", "3", "#", "4", "$", "5", "%", "6", "^", "7" \
, "&", "8", "*", "9", "(", "0", ")", "-", "_", "=", "+", "[", "{", "]", "}" \
, "\\", "|", ";", ":", "'", "\"", ",", "<", ".", ">", "/", "?"]
index = 0
for character in countList:
if character == mostFrequent:
print(characterKey[index], "is most frequent.")
index += 1
答案 0 :(得分：2)
您正在处理的问题之一是
elif character == "T" or "t"
不像你想象的那样工作。你必须重新重写表达式的左手边，如下所示：
elif character == "T" or character == "t"
或者您可以使用in运算符：
elif character in ("T,"t")
但是，更改此功能并不能完全解决您的问题。
有助于使代码更清晰，更快的一件事是将所收到的字符值转换为整数值，然后使用整数值作为将字符放入右侧索引的方法。阵列。我会把这个练习留给你：）
答案 1 :(得分：1)
我认为使用dict可以节省一些代码。 .lower（）可以防止你必须检查每个，因为我假设你的目的与'T'等效。请注意，辅助函数需要一个非空的字符串。希望这可以帮助
def get_character_frequency(user_input):
'''return dictionary of frequencies to characters'''
char_freq_dict = {}
freq_char_dict = {}
#create dict with characters as keys and freqs as values
for character in user_input:
char_freq_dict[character] = char_freq_dict.get(character, 0) + 1
#invert dict
for character, freq in char_freq_dict.items():
if freq in freq_char_dict.keys():
freq_char_dict[freq].append(character)
else:
freq_char_dict[freq] = [character]
return freq_char_dict
def main():
#you could add some code to ensure some text is entered, or
#modify to error check for this
userInput = input("Enter String: ").lower()
freq_char_dict = get_character_frequency(userInput)
max_freq, max_char = sorted(freq_char_dict.items(), reverse=1)[0]
print('\n{} characters were entered'.format(len(userInput)))
print('Most frequent character(s) {}'.format(max_char), end=" ")
print('Ocurring {} time(s)'.format(max_freq))
main()
答案 2 :(得分：0)
这会对你有帮助。
import re
import itertools
import operator
def most_common(L):
# get an iterable of (item, iterable) pairs
SL = sorted((x, i) for i, x in enumerate(L))
# print 'SL:', SL
groups = itertools.groupby(SL, key=operator.itemgetter(0))
# auxiliary function to get "quality" for an item
def _auxfun(g):
item, iterable = g
count = 0
min_index = len(L)
for _, where in iterable:
count += 1
min_index = min(min_index, where)
# print 'item %r, count %r, minind %r' % (item, count, min_index)
return count, -min_index
# pick the highest-count/earliest item
return max(groups, key=_auxfun)[0]
user_input = [_.lower() for _ in raw_input("Enter String: ")]
frequent = most_common(list(user_input))
print "Most frequent entry:",frequent
print "Number of Occerences:",user_input.count(frequent)
输出：
Enter String: aAbBBcccC12309u/.,;'/*
Most frequent entry: c
Number of Occerences: 4