扫描程序类跳过代码

Question

所以我有一个并不复杂的方法，但它似乎是在我拥有的while循环中跳过2行代码。我尝试了一个Do-while和一个普通的while循环，这两个都没有帮助。这是代码：

        do
    {
        System.out.println("Enter a building material that you would like to add :: ");
        String first = keyboard.nextLine();
        System.out.println("How many of that material would you like to add ::");
        int second = keyboard.nextInt();
        int i = (int)item.getID(first);

            //long section of code here. It's not necessary

        System.out.println("");
        System.out.println("Lumber - " + lumber);
        System.out.println("Plywood - " + plywood);
        System.out.println("Cinderblocks - " + cinder);
        System.out.println("Mortar - " + mortar);
        System.out.println("Tank Traps - " + tanktrap);
        System.out.println("Metal Poles - " + metalpole);
        System.out.println("");

        System.out.println("Would you like to add more materials? (yes / no) :: ");
        String response = keyboard.next();
        if(response.equalsIgnoreCase("yes"))
        {
            wantsNext = true;
        }else{
            wantsNext = false;
        }


    }while(wantsNext);

输出结果如下：

Welcome to OGx_Killer's Epoch Building Supplies Calculator
Enter a building material that you would like to add :: 
cinderblock wall
How many of that material would you like to add ::
10

Lumber - 0
Plywood - 0
Cinderblocks - 70
Mortar - 20
Tank Traps - 0
Metal Poles - 0

Would you like to add more materials? (yes / no) :: 
yes
Enter a building material that you would like to add :: 
How many of that material would you like to add ::

正如你所看到的，第二次在循环中，它跳过第一个输入，留下第二个输入被回答，使循环无用。任何帮助将不胜感激。我感觉这是我正在使用的扫描仪方法的问题。它可能需要不是keyboard.nextLine（）。非常感谢！

Answer 1

<强>问题：

String first = keyboard.nextLine();

问题是它会消耗用户输入的keyboard.next();的新行“\ n”，从而跳过它。

<强>溶液

改为使用next()。

或

致电next()致电nextLine()以消费"\n"

后

<强>样品：

System.out.println("Would you like to add more materials? (yes / no) :: ");
String response = keyboard.next();
keyboard.nextLine();