我有一个输入：
</name> rahul is nice guy <version=name> previous name is manoj </version> and cool </s>
我正在使用正则表达式
re.search(r'(</name>([a-z0-9]+)(?!<version>(.*?)</version>)([a-z0-9]+)</s>)', line, re.M|re.I)
我的输出应该是：
rahul is nice guy and cool
它与模式不匹配，我试图在'版本'标签之间省略单词，有人可以告诉我哪里出错了吗？
用python编写。
答案 0 :(得分：3)
此模式匹配：
</name>([a-z0-9 ]+)<version=name>(.*?)</version>([ a-z0-9]+)</s>
请注意空格[a-z0-9 ]，并记下您忘记的字符=name。
当然，你必须参加第一场比赛和第三场比赛。
如果是python - 获取文本而不是版本名称中的文本：
Matches = re.findall(r'</name>([a-z0-9 ]+)<version=name>(.*?)</version>([ a-z0-9]+)</s>', line, re.M|re.I)
FinalText = Matches[0] + Matches[2]
答案 1 :(得分：0)