Question

我想要使用带有SSRS的图表来表示一些数据。在我生成此报告之前，我正在尝试考虑确实存在的数据。我已经设置了一个小型数据集市，它汇总了每日总数。对于某些组，特定周的数据不存在。我正在寻找一种方法来计算这些数据，所以当我开始生成报告时，线图表示实际数据，0表示确实存在的值。举个例子：

yearnbr     weeknbr      restaurant     mealsserved
 2014        1           Joes Pasta     5
 2014        2           Joes Pasta     4
 2014        4           Joes Pasta     2

通过上面的例子，第三周的数据不存在。我想生成一个可以在第3周插入0或null值的查询。当我生成报告时，第2周和第4周的数据连接。我需要在第3周插入0或Null。我使用的是SQL Server 2008 R2。

Answer 1

您需要有一个结果集才能加入。

您可以动态生成它：

WITH    weeks (w) AS
        (
        SELECT  1
        UNION ALL
        SELECT  w + 1
        FROM    weeks
        WHERE   w < 54
        )
SELECT  *
FROM    weeks
LEFT JOIN
        sales
ON      year = 2014
        AND weeknbr = w

但表现会很糟糕。

最好使用数字创建和填充表格（一次）：

CREATE TABLE num (n INT NOT NULL PRIMARY KEY)

WITH    q (n) AS
        (
        SELECT  1
        UNION ALL
        SELECT  n + 1
        FROM    q
        WHERE   n < 100000
        )
INSERT
INTO    num
SELECT  n
FROM    q

然后在上面的查询中使用它：

SELECT  *
FROM    num
LEFT JOIN
        sales
ON      year = 2014
        AND weeknbr = n

Answer 2

测试数据

DECLARE @TABLE TABLE 
  (
   yearnbr     INT,
   weeknbr     INT,
   restaurant  VARCHAR(20),
   mealsserved INT
   )
INSERT INTO @TABLE VALUES 
 (2014 ,1 ,'Joes Pasta',5),
 (2014 ,2 ,'Joes Pasta',4),
 (2014 ,4 ,'Joes Pasta',2)

查询

SELECT COALESCE(yearnbr,[Year]) AS yearnbr
      ,COALESCE(weeknbr,[Week]) AS weeknbr
      ,ISNULL(restaurant, '')   AS restaurant
      ,ISNULL(mealsserved, 0)   AS mealsserved 
FROM @TABLE t RIGHT JOIN 
                    (
                    VALUES (YEAR(GETDATE()), 1),
                           (YEAR(GETDATE()), 2),
                           (YEAR(GETDATE()), 3),
                           (YEAR(GETDATE()), 4)
                    ) A([Year],[Week])
ON t.yearnbr = A.[Year] AND t.weeknbr = A.[Week]

结果

╔═════════╦═════════╦════════════╦═════════════╗
║ yearnbr ║ weeknbr ║ restaurant ║ mealsserved ║
╠═════════╬═════════╬════════════╬═════════════╣
║    2014 ║       1 ║ Joes Pasta ║           5 ║
║    2014 ║       2 ║ Joes Pasta ║           4 ║
║    2014 ║       3 ║            ║           0 ║
║    2014 ║       4 ║ Joes Pasta ║           2 ║
╚═════════╩═════════╩════════════╩═════════════╝

Answer 3

您可以Join到周数表。您可以尝试以下一个想法：

Declare @Week Table (N TinyInt Not Null)
Insert  @Week Values (0),(1),(2),(3),(4),(5),(6),(7),(8),(9) 

Select  *
From    Table   T
Right Join
(
    Select      (A.N + (10 * B.N))  Week
    From        @Week   A
    Cross Join  @Week   B
) W On T.weeknbr = W.Week
Where   W.Week Between 1 And 52
Order By W.Week

为不存在的数据生成0或Null值

3 个答案: