Question

我知道有几个人会问同一个主题，但我无法从这些问题中找到问题的答案。我有以下代码，

$.post("show_search_results.php", {location_name: ""+location_name+"", key: ""+key+"", category_id: ""+category_id+"", page_number: ""+page_number+""}, function(data){
if(data.length >0){
    var dataArray = JSON.parse(data);
    var result_count=(dataArray.root.data.partners).length;
    if(result_count > 0){
        //block a;
    }else if(s_limit==0){
        //block b;
    }else{
        //block c;
    }
}});

我使用php作为后端。这段代码在我的本地服务器上工作正常，并在使用以下json的实时服务器中正常工作。

{"root": {"success":"1","message":"Successfully retrieved data.","data":{"partners":[{"store_name":"Mega Mart (Readymade Brands)","store_address":"Next to SBI, Vyttila, Ernakulam","store_phone":"","item_name":"Festival of Young at 999","item_description":"Megamart celebrates the spirit of being young. Take home 4 groovy T-shirts or 2 stylish shirts  or 3 women kurtas for just rupees 999.","item_offer":"999 Offer","offer_expiry":"2014-06-08","tag1":"T-shirt","tag2":"Dress","tag3":"Jeans","store_id":"a9e12c46-ee00-11e3-a5e4-bc305be6e93e"}]}}}

但对于这个json，

{"root": {"success":"2","message":"no results found","data":{"partners":[]}}}

在实时服务器中显示，

SyntaxError: JSON.parse: unexpected character
var dataArray = JSON.parse(data);

我试图从我的代码中删除JSON.parse，但它显示

TypeError: dataArray.root is undefined
var array_locations=dataArray.root.data.locations;

请帮我找一个解决方案。感谢。

Answer 1

所以你不应该手动做JSON.parse - jQuery可以为你做这个，如果你告诉它期待JSON。它通常在返回响应中使用Content-Type标头，但您可以告诉它解析JSON：

$.post({
    url: "show_search_results.php", 
    data: {
        location_name: ""+location_name+"", 
        key: ""+key+"", 
        category_id: ""+category_id+"", 
        page_number: ""+page_number+""
    }, 
    dataType: "json",
    success: function(data){
        // do something with data here...
        alert(data.root.message);
    }
});

顺便说一句 - 我尝试将您指定的JSON放入Chrome调试控制台的JSON.parse，它运行正常。 JSON没有错。

Answer 2

像这样改变你的状况。

if(data.length >0){
    var dataArray = JSON.parse(data);

    if(typeof dataArray.root != undefined && dataArray.root.success == 1) {
        // Success
    }
    else {
       // Failure
    }
}

SyntaxError：JSON.parse：null结果的意外字符

2 个答案: