最近我们最终将项目转换为Java 1.6。在执行测试时,我发现使用1.6时,不抛出使用1.5抛出的SAXParseException。
以下是我的测试代码,用于演示此问题。
import java.io.StringReader;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.SchemaFactory;
import org.junit.Test;
import org.xml.sax.InputSource;
import org.xml.sax.SAXParseException;
/**
* Test class to demonstrate the difference between JDK 1.5 to JDK 1.6.
*
* Seen on Linux:
*
* <pre>
* #java version "1.6.0_18"
* Java(TM) SE Runtime Environment (build 1.6.0_18-b07)
* Java HotSpot(TM) Server VM (build 16.0-b13, mixed mode)
* </pre>
*
* Seen on OSX:
*
* <pre>
* java version "1.6.0_17"
* Java(TM) SE Runtime Environment (build 1.6.0_17-b04-248-10M3025)
* Java HotSpot(TM) 64-Bit Server VM (build 14.3-b01-101, mixed mode)
* </pre>
*
* @author dhiller (creator)
* @author $Author$ (last editor)
* @version $Revision$
* @since 12.03.2010 11:32:31
*/
public class TestXMLValidation {
/**
* Tests the schema validation of an XML against a simple schema.
*
* @throws Exception
* Falls ein Fehler auftritt
* @throws junit.framework.AssertionFailedError
* Falls eine Unit-Test-Pruefung fehlschlaegt
*/
@Test(expected = SAXParseException.class)
public void testValidate() throws Exception {
final StreamSource schema = new StreamSource( new StringReader( "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"
+ "<xs:schema xmlns:xs=\"http://www.w3.org/2001/XMLSchema\" "
+ "elementFormDefault=\"qualified\" xmlns:xsd=\"undefined\">" + "<xs:element name=\"Test\"/>" + "</xs:schema>" ) );
final String xml = "<Test42/>";
final DocumentBuilderFactory newFactory = DocumentBuilderFactory.newInstance();
newFactory.setSchema( SchemaFactory.newInstance( "http://www.w3.org/2001/XMLSchema" ).newSchema( schema ) );
final DocumentBuilder documentBuilder = newFactory.newDocumentBuilder();
documentBuilder.parse( new InputSource( new StringReader( xml ) ) );
}
}
当使用JVM 1.5测试通过时,在1.6上它失败并出现“预期的异常SAXParseException”。
DocumentBuilderFactory.setSchema(Schema)方法的Javadoc说:
当发现错误时 验证器,解析器负责 将它们报告给用户指定的 ErrorHandler(或错误处理程序 未设置,忽略它们或抛出 他们),就像任何其他错误一样 由解析器本身找到。其他 单词,如果是用户指定的 ErrorHandler已设置,必须接收 那些错误,如果没有,它们必须是 按照治疗方法治疗 实现特定的默认错误 处理规则。
DocumentBuilder.parse(InputSource)方法的Javadoc说:
BTW:我尝试通过setErrorHandler设置错误处理程序,但仍然没有异常。
现在我的问题:
什么更改为1.6,阻止架构验证抛出SAXParseException?它与我试图解析的模式或xml有关吗?
更新
以下代码适用于1.5和1.6,因为我一直希望:
@Test(expected = SAXParseException.class)
public void testValidate() throws Exception {
final StreamSource schema = new StreamSource( new StringReader( "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"
+ "<xs:schema xmlns:xs=\"http://www.w3.org/2001/XMLSchema\" "
+ "elementFormDefault=\"qualified\" xmlns:xsd=\"undefined\">" + "<xs:element name=\"Test\"/>" + "</xs:schema>" ) );
final String xml = "<Test42/>";
final DocumentBuilderFactory newFactory = DocumentBuilderFactory.newInstance();
final Schema newSchema = SchemaFactory.newInstance( "http://www.w3.org/2001/XMLSchema" ).newSchema( schema );
newFactory.setSchema( newSchema );
final Validator newValidator = newSchema.newValidator();
final Source is = new StreamSource( new StringReader( xml ) );
try {
newValidator.validate( ( Source ) is );
}
catch ( Exception e ) {
e.printStackTrace();
throw e;
}
final DocumentBuilder documentBuilder = newFactory.newDocumentBuilder();
documentBuilder.parse( new InputSource( new StringReader( xml ) ) );
}
解决方案似乎是显式使用从Schema实例创建的Validator实例。 我找到了解决方案here
我还不确定那是为什么......
答案 0 :(得分:1)
显然,不符合架构的文档只能对默认错误处理程序中的stderr进行温和的指责。我的解决方案是用更严格的错误处理程序替换默认错误处理程序:
// builder is my DocumentBuilder
builder.setErrorHandler(new ErrorHandler() {
@Override
public void error(SAXParseException arg0) throws SAXException {
throw arg0;
}
@Override
public void fatalError(SAXParseException arg0) throws SAXException {
throw arg0;
}
@Override
public void warning(SAXParseException arg0) throws SAXException {
throw arg0;
}
});