Question

当覆盖表单清理方法时，您如何知道它在任何字段上的验证失败？例如在下面的表格中，如果我覆盖了干净的方法，我如何知道表格在任何字段上的验证是否失败？

class PersonForm(forms.Form):
    title = Forms.CharField(max_length=100)
    first_name = Forms.CharField(max_length=100)
    surname = Forms.CharField(max_length=100)
    password = Forms.CharField(max_length=100)

def clean(self, value):
    cleaned_data = self.cleaned_data

    IF THE FORM HAS FAILED VALIDATION:
        self.data['password'] = 'abc'
        raise forms.ValidationError("You have failed validation!")
    ELSE:
        return cleaned_data

由于

Answer 1

您可以检查是否有任何错误添加到错误字典中：

def clean(self, value):
    cleaned_data = self.cleaned_data

    if self._errors:
        self.data['password'] = 'abc'
        raise forms.ValidationError("You have failed validation!")
    else:
        return cleaned_data

奖金！您可以检查特定字段的错误：

def clean(self, value):
    cleaned_data = self.cleaned_data

    if self._errors and 'title' in self._errors:
        raise forms.ValidationError("You call that a title?!")
    else:
        return cleaned_data

Answer 2

如果您的数据无法验证，请执行表单实例不会有 cleaning_data属性

Django Doc on Accessing "clean" data

使用self.is_valid()。

Answer 3

虽然它的旧帖子，如果您想在同一表单/模型表格的多个字段上应用验证，请使用clean()。此方法返回 cleaning_data 字典。

要向用户显示错误，您可以使用add_error(<fieldname>, "your message")方法。这将在表单顶部显示错误以及字段名称。示例如下所示：

add_error()会自动从 cleaning_data 词典中删除该字段，您无需手动删除该字段。此外，你不必导入任何东西来使用它。

documentation is here

def clean(self):

  if self.cleaned_data['password1'] != self.cleaned_data['password2']:
    msg = 'passwords do not match'
    self.add_error('password2', msg)

  return self.cleaned_data

如果您只想在表单/模型的单个字段上进行验证，请使用clean_<fieldname>()。此方法将使用 cleaning_data 字典中的值，然后您可以检查逻辑错误。检查逻辑后，始终返回值。

def clean_password(self):

  password = self.cleaned_data['password']

  if len(password)<6:
    msg = 'password is too short'
    self.add_error('password', msg)

  return password

Answer 4

以下是在clean()中覆盖django.forms.Form并在django-braces中使用AnonymousRequiredMixin要求只有匿名用户访问Loing页面的简单示例：

class LoginView(AnonymousRequiredMixin, FormView):
    """
    Main Login. And Social Logins
    """
    template_name = 'core/login.html'
    form_class = LoginForm
    success_url = reverse_lazy('blog:index')

    def get_success_url(self):
        try:
            next = self.request.GET['next']
        except KeyError:
            next = self.success_url
        return next

    def form_valid(self, form):
        cd = form.cleaned_data
        user = auth.authenticate(username=cd['login_username'], 
            password=cd['login_password'])
        if user:
            auth.login(self.request, user)
            messages.info(self.request, 'You are logged in.')
        return super(LoginView, self).form_valid(form)

django覆盖表单清理方法

4 个答案: