参数不作为命名参数存在

Question

我的查询是这样的：

Query query1 = session.createQuery("select c.email from Contact c where c.contactNo =:contactNo");
    query1.setInteger("contactNo", 22);

我得到的错误是：

  

线程“main”中的异常java.lang.IllegalArgumentException：   参数contactNo不作为[select中的命名参数存在   来自Contact c的c.email，其中c.contactNo =？]

工作正常

Query query = session.createQuery("select c.email from Contact c where c.contactNo = ?");
    query.setInteger(0, 22);

为什么第一个查询不起作用？

Answer 1

Query query1 = session.createQuery("select c.email from Contact c where c.contactNo =:contactNo");
query.setParameter("contactNo", 22);

尝试使用setParameter而不是setInteger

Answer 2

  Just Try this 


    **Step 1--:** Add How many parameter you need just add in hashmap
   -------------------------------------------------------------------
    
    HashMap param_List=new HashMap();
    param_List.put("contactNo",22);

    
    **Step 2--:** Just You pass your Query
   -------------------------------------------------------------------
    
    Query query1 = session.createQuery("select c.email from Contact c where c.contactNo =:contactNo");


  **Step 3--:** What ever Data type is no matters but get an output.
  -------------------------------------------------------------------

    for(Object paramKey : param_List.keySet())
    {
    query1.setParameter(paramkey.toString(), param_List.get(paramKey);
    }


 **Step 4--:**
-------------------------------------------------------------------
    String finalResult=query1.getSingleResult().toString();

Answer 3

我认为你的参数可能需要一个空格：

Query query1 = session.createQuery("select c.email from Contact c where c.contactNo = :contactNo");
query.setInteger("contactNo", 22);