Question

http://myside.com/MyControllers/213123123给了我Couldn't find MyController with id=213123123

def show
  render :text=>'testing ....'  
  begin
    @ingredient = MyController.find(params[:id])
  rescue RecordNotFound => e
    puts "Test........"
  end
  respond_to do |format|
    format.html # show.html.erb
    format.json { render json: @ingredient }
  end
end

渲染：text =＆gt;＆＃39;测试......＆＃39;如果给出无效ID ，则不会报复无法找到id = 213123123

的MyController

任何人都会指导我正确的语法

Answer 1

您有几个重要的语法问题：

您的路线似乎格式错误（you need to use snake_case rather than CamelCase）

您最好使用exception_app中间件挂钩来捕获异常

我会按如下方式解决这些问题：

#config/routes.rb
resources :my_controllers #-> domain.com/my_controllers/:id

#app/controllers/my_controllers_controller.rb
Class MyController < ApplicationController
   def show
       @ingredient = MyController.find params[:id]
   end
end

exceptions_app

我实际上已经写了很多关于这个here＆amp; written a gem here＆amp;有一个很棒的github gist here

这将使您能够使用exceptions_app中间件钩子捕获任何异常：

#config/application.rb
config.exceptions_app = ->(env) { ExceptionController.action(:show).call(env) }

这将允许您通过名为ExceptionController的单独控制器路由任何异常：

#app/controllers/exception_controller.rb
Class ExceptionController < ApplicationController
   layout 'application'

   def show
     @exception       = env['action_dispatch.exception']
     @status_code     = ActionDispatch::ExceptionWrapper.new(env, @exception).status_code
     @rescue_response = ActionDispatch::ExceptionWrapper.rescue_responses[@exception.class.name]

     respond_to do |format|
       format.html { render :show, status: @status_code, layout: !request.xhr? }
       format.xml  { render xml: details, root: "error", status: @status_code }
       format.json { render json: {error: details}, status: @status_code }
     end
  end
end

#app/views/exception/show.html.erb
Put what you want here

这将帮助您捕获异常 - 如果您想在开发中进行测试，则应该执行此操作：

#config/environments/development.rb
config.consider_all_requests_local = false

无法找到id = 213123123的MyController

1 个答案: