我有一个 JSON 这样的数组,
JSONArray content=
"[
{"+"\"pageid\":\"19\","+"\"company\":"+"\"C1\","+"\"pageview\":"+"\"10\","+"\"visitfreq\":"+"\"2\"},{"+"\"pageid\":\"19\","+"\"company\":"+"\"C2\","+"\"pageview\":"+"\"20\","+"\"visitfreq\":"+"\"4\"},{"+"\"pageid\":\"200\","+"\"company\":"+"\"C3\","+"\"pageview\":"+"\"30\","+"\"visitfreq\":"+"\"3\"}
]";
JSONArray的代码:
JSONObject jObj1 = new JSONObject();
jObj1.put("pageid", "19");
jObj1.put("company", "C1");
jObj1.put("pageview", "10");
jObj1.put("visitfreq", "2");
JSONObject jObj2 = new JSONObject();
jObj2.put("pageid", "19");
jObj2.put("company", "C2");
jObj2.put("pageview", "20");
jObj2.put("visitfreq", "4");
JSONObject jObj3 = new JSONObject();
jObj3.put("pageid", "200");
jObj3.put("company", "C3");
jObj3.put("pageview", "30");
jObj3.put("visitfreq", "3");
JSONArray jArr = new JSONArray();
jArr.put(jObj1);
jArr.put(jObj2);
jArr.put(jObj3);
[
{
"company": "C1",
"visitfreq": "2",
"pageview": "10",
"pageid": "19"
},
{
"company": "C2",
"visitfreq": "4",
"pageview": "20",
"pageid": "19"
},
{
"company": "C3",
"visitfreq": "3",
"pageview": "30",
"pageid": "200"
}
]
我已经努力获得下面的输出
这样的出局
[{pageid},[{rest of details}] ,{pageid},[{rest of details}] ]
如果同一个pageid多次出现
它应该是这样的
[{pageid},[{rest of details1},{rest of details2},.. ],{pageid},[{rest of details}] ]
答案 0 :(得分:0)
您似乎需要创建一个映射Map
的{{1}}。
获得pageid : [{rest of details1},{rest of details2},.. ]
后,您可以将其转换为所需的输出。
以下代码将使用Map
(上面代码中的代码)并将其转换为JSONArray
。
Map<String, JSONArray>
以下是它的样子:
public Map<String, JSONArray> getJsonArrayAsMapOnPageId(JSONArray inputArr) throws JSONException {
//Map holding pageid : [{company:"",pageview:"",visitfreq:""}, ... , ...] mappings
Map<String, JSONArray> idMap = new HashMap<String, JSONArray>();
for (int i=0; i < inputArr.length(); i++) {
JSONObject inputObj = inputArr.getJSONObject(i);
String id = inputObj.getString("pageid");
JSONArray jObjList;
if (idMap.containsKey(id)) {
//append to existing list in the Map
jObjList = idMap.get(id);
} else {
//create new list
jObjList = new JSONArray();
}
JSONObject newJsonObj = new JSONObject();
newJsonObj.put("company", inputObj.get("company"));
newJsonObj.put("pageview", inputObj.get("pageview"));
newJsonObj.put("visitfreq", inputObj.get("visitfreq"));
jObjList.put(newJsonObj);
idMap.put(id, jObjList);
}
return idMap;
}
这是我得到的:
System.out.println("Map looks like:\n" + pageidMap);
我不确定您希望此输出以什么形式(对象,打印到输出等),因此您可以做最后一点将此{
200=[
{
"company": "C3",
"visitfreq": "3",
"pageview": "30"
}
],
19=[
{
"company": "C1",
"visitfreq": "2",
"pageview": "10"
},
{
"company": "C2",
"visitfreq": "4",
"pageview": "20"
}
]
}
转换为{{1没有问题。