Question

我有一个c＃应用程序A启动另一个c＃应用程序B，如下所示：

string baseDir = AppDomain.CurrentDomain.BaseDirectory;
string path = baseDir + "Programs\\Logging\\";
Process logger = new Process();
logger.StartInfo.FileName = System.IO.Path.Combine(path, "Logger.exe");
logger.Start();

在Logger.exe中，我执行以下操作：

string dir = Directory.GetCurrentDirectory();

但是它告诉我dir是启动它的原始程序A的目录，而不是它自己的目录（Programs \ Logging）

为什么这？??

Answer 1

这是正确的目录。它是您从中启动该进程的工作目录。如果您想更改它，请执行以下操作：

string baseDir = AppDomain.CurrentDomain.BaseDirectory;
string path = baseDir + "Programs\\Logging\\";
Process logger = new Process();
// Here's the deal
logger.StartInfo.WorkingDirectory = path;
logger.StartInfo.FileName = System.IO.Path.Combine(path, "Logger.exe");
logger.Start();

Answer 2

每个MSDN，The current directory is distinct from the original directory, which is the one from which the process was started.

http://msdn.microsoft.com/en-us/library/system.io.directory.getcurrentdirectory(v=vs.110).aspx

所以，它正在做正确的事。

Directory.GetCurrentDirectory（）;报告第二个exe的错误路径

2 个答案: