Question

以下代码是使用DOM解析器来反转XML。一切正常，但问题是属性没有逆转对于前：＆lt; element att1 =＆＃34; foo＆＃34; ATT2 =＆＃34;杆＆＃34; /＆GT; 结果应该是＆lt; element att2 =＆＃34; bar＆＃34; ATT2 =＆＃34;富＆＃34; /＆GT;

如何反转XML属性？

public static void main(String[] args) throws Exception {
    reverseChildElements();
}

public static void reverseChildElements() {
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    Document doc = null;
    try {
        DocumentBuilder builder = factory.newDocumentBuilder();
        // Parse the input xml file
        doc = builder.parse("file.xml");
        Node firstChild = doc.getFirstChild();
        reverseChildNodes(firstChild);
        doc.replaceChild(firstChild, doc.getFirstChild());
        outputXml(doc);
    } catch (ParserConfigurationException | SAXException | IOException | TransformerException e) {
        e.printStackTrace();
    }
}

private static void reverseChildNodes(Node firstChild) {
    NodeList childNodes = firstChild.getChildNodes();
    Stack<Node> nodeStack = new Stack<Node>();
    // Put all the nodes into a Stack
    for (int i = 0; i < childNodes.getLength(); i++) {
        reverseChildNodes(childNodes.item(i));
        revereseAttributes(childNodes.item(i));
        nodeStack.push(childNodes.item(i));
    }
    // This is the last one which we entered
    while (!nodeStack.empty()) {
        firstChild.appendChild(firstChild.removeChild(nodeStack.pop()));
    }
}

private static void revereseAttributes(Node item) {
    if(item.hasAttributes() && item.getAttributes().getLength() > 1){
        NamedNodeMap attributesMap = item.getAttributes();
        List<Node> nodeStack = new ArrayList<Node>();
        for (int i = 0; i < attributesMap.getLength(); i++) {
            nodeStack.add(attributesMap.item(i));
        }
        for (Node node : nodeStack) {
            attributesMap.removeNamedItem(node.getNodeName());
            Attr atr = node.getOwnerDocument().createAttribute(node.getNodeName());
            atr.setValue(node.getNodeValue());
            attributesMap.setNamedItem(atr);
        }
    }

}

private static void outputXml(Document doc) throws TransformerException {
    TransformerFactory tf = TransformerFactory.newInstance();
    StringWriter writer = null;
        Transformer transformer = tf.newTransformer();
        transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION,
                "yes");
        writer = new StringWriter();

        transformer.transform(new DOMSource(doc), new StreamResult(writer));
    System.out.println(writer.toString().replaceAll( "(?s)<!--.*?-->", "" ));
}

Answer 1

根据定义，XML属性不是有序的。它们在XML文档中的出现（在其包含元素中）完全受到某些XML编写器的实现的支配。

没有XML处理器可以基于属性外观顺序的任何逻辑。

那就是说，你应该满足于能够扭转元素。

Java -Reverse XML属性

1 个答案: