Question

我在SQL Server 2005中使用以下查询返回了以下结果。现在，我想添加一个业务规则。如果partnumber有一个与之关联的工厂，并且它不是我当前没有检查的工厂，那么它应该列为零。

对于xample，在以下结果中，工厂 - 部件号组合96-ABC应该将总和返回为零。但是11-DEF组合应该继续显示为50.而所有其他值应该返回与现在相同的结果。

如何修改此查询？虽然我试过几个小时，但还没有达成解决方案。

解释：对于下面突出显示的行，partnumber为ABC。但是该部分与工厂“96”没有任何关系，因为你可以看到MHL和MMHP表中的数据......（这与DEF情景类似）....但是partnumber与其他plants（20和21）有关联 - 因此该部分有restricted association，它应该显示为植物“96”的零 ....对于DEF部分，所有植物都是OPEN association - 因此所有行项目的总和应该是SumQty（即现在显示的50）

注意：我们可以在一个查询中获取它吗？分成两个查询并进行更新对我不起作用。

当前结果

enter image description here

数据

DECLARE @MHL TABLE (LineNumber VarCHAR(5), PartNumber VARCHAR(10), Qty INT)


INSERT INTO @MHL VALUES ('10001','ABC',10)
INSERT INTO @MHL VALUES ('10002','ABC',100)
INSERT INTO @MHL VALUES ('10003','DEF',50)
INSERT INTO @MHL VALUES ('10005','KXY',25)
INSERT INTO @MHL VALUES ('10006','KXY',30)


DECLARE @MHP TABLE (PlantCode VarCHAR(5), LineNumber VARCHAR(5))
INSERT INTO @MHP VALUES ('20','10001')
INSERT INTO @MHP VALUES ('21','10002')
INSERT INTO @MHP VALUES ('80','10005')
INSERT INTO @MHP VALUES ('80','10006')


DECLARE @MasterPLantParts TABLE (PlantCode VarCHAR(5), PartNumber VARCHAR(10))

INSERT INTO @MasterPLantParts VALUES ('20','ABC')
INSERT INTO @MasterPLantParts VALUES ('21','ABC')
INSERT INTO @MasterPLantParts VALUES ('96','ABC')
INSERT INTO @MasterPLantParts VALUES ('11','DEF')
INSERT INTO @MasterPLantParts VALUES ('80','KXY')

选择查询

select 
  mpp.PlantCode PlantCode, 
  mpp.PartNumber PartNumber,
  sum(MHL.Qty) as SumQty
from @MasterPLantParts mpp
left outer join @MHP MHP 
    on mpp.PlantCode = MHP.PlantCode
inner join @MHL MHL 
    on (
        MHL.LineNumber = MHP.LineNumber 
        or (
             mpp.PartNumber = MHL.PartNumber
             and MHP.LineNumber is null
            )
        )
group by mpp.PlantCode, mpp.PartNumber
order by mpp.PlantCode, mpp.PartNumber

Answer 1

我认为这可能是你想要的，你需要分步进行......

select mpp.PlantCode PlantCode, mpp.PartNumber PartNumber, sum(IsNull(mhl.Qty,0)) as Qty
into #tt
from @MasterPLantParts mpp
left join @MHP MHP on mpp.PlantCode = MHP.PlantCode
left join @MHL mhl on (mhl.PartNumber = mpp.PartNumber and mhl.LineNumber = mhp.LineNumber)
group by mpp.PlantCode, mpp.PartNumber
order by mpp.PlantCode, mpp.PartNumber


update tt
set Qty = mhl.Qty
FROM #tt tt
inner join @MHL mhl on (mhl.PartNumber = tt.PartNumber)
where tt.Qty=0
  and not exists (select 1 from @MasterPLantParts mpp where mpp.PlantCode<>tt.PlantCode and mpp.PartNumber=tt.PartNumber)

select * from #tt
drop table #tt

这会产生......

PlantCode PartNumber SumQty
20        ABC         10
21        ABC         100
96        ABC         0
11        DEF         50
80        KXY         55

作为单个选择语句，可以按如下方式完成......

select mpp.PlantCode PlantCode, mpp.PartNumber PartNumber, Sum(case mhl2.RecCount
                                                                when 1 then mhl2.Qty
                                                                ELSE IsNull(mhl.Qty,0) END) as Qty
from @MasterPLantParts mpp
left join @MHP MHP on mpp.PlantCode = MHP.PlantCode
left join @MHL mhl on (mhl.PartNumber = mpp.PartNumber and mhl.LineNumber = mhp.LineNumber)
left join (select PartNumber, count(1) RecCount, Sum(Qty) as Qty
            from @MHL
            group by PartNumber
            having count(1)=1) mhl2 on (mhl2.PartNumber = mpp.PartNumber)
group by mpp.PlantCode, mpp.PartNumber

Answer 2

以下查询可以获得所需的结果。首先，选择MasterPLantParts中的所有行（使用LEFT OUTER JOIN）。然后，用MHL进行连接。如果给定工厂的MHP中没有条目，则选择MHL的所有生产线。

使用MHP中可用的不同部件制作额外的LEFT OUTER JOIN（mhl_parts）。如果某个部件在MHP中根本不可用，那么总和将根据所有线路的MHL计算。否则，它将为零。

select 
  mpp.PlantCode PlantCode, 
  mpp.PartNumber PartNumber,
  sum(case
      when (MHP.LineNumber is null and mhl_parts.PartNumber is null) or 
        (MHP.LineNumber is not null and mhl_parts.PartNumber is not null)
      then MHL.Qty
      else 0
  end) SumQty
from MasterPLantParts mpp
left outer join MHP on mpp.PlantCode = MHP.PlantCode
left outer join
(
  select DISTINCT MHL.PartNumber PartNumber
  from MHL
  INNER JOIN MHP ON MHP.LineNumber = MHL.LineNumber
) mhl_parts
on mhl_parts.PartNumber = mpp.PartNumber
inner join MHL on MHL.LineNumber = MHP.LineNumber or (mpp.PartNumber = MHL.PartNumber and MHP.LineNumber is null)
group by mpp.PlantCode, mpp.PartNumber
order by mpp.PlantCode, mpp.PartNumber;

SQL Fiddle

Oracle 8i语法：

select 
  mpp.PlantCode PlantCode, 
  mpp.PartNumber PartNumber,
  sum(case
      when (MHP.LineNumber is null and mhl_parts.PartNumber is null) or 
        (MHP.LineNumber is not null and mhl_parts.PartNumber is not null)
      then MHL.Qty
      else 0
  end) SumQty
from MasterPLantParts mpp, MHP, MHL,
    (
      select DISTINCT MHL.PartNumber PartNumber
      from MHL
      INNER JOIN MHP ON MHP.LineNumber = MHL.LineNumber
    ) mhl_parts
where mpp.PlantCode = MHP.PlantCode(+)
and mpp.PartNumber = mhl_parts.PartNumber(+)
and (MHL.LineNumber = MHP.LineNumber or (mpp.PartNumber = MHL.PartNumber and MHP.LineNumber is null))
group by mpp.PlantCode, mpp.PartNumber
order by mpp.PlantCode, mpp.PartNumber;

Answer 3

这是一个查询。我改变了这个逻辑。

首先，我从MHP和MHL表中收集数据，计算数据总和。

然后加入他们。

;WITH twoInOne AS (

    SELECT MHP.PlantCode, MHL.PartNumber, SUM(MHL.Qty) AS Qty
    FROM @MHL AS MHL
    LEFT JOIN @MHP AS MHP
        ON MHL.LineNumber = MHP.LineNumber 
    GROUP BY MHP.PlantCode, MHL.PartNumber

)
SELECT 
  mpp.PlantCode PlantCode, 
  mpp.PartNumber PartNumber,
  CASE 
    WHEN tIO.PlantCode IS NOT NULL THEN tIO.Qty
    WHEN tIO2.PlantCode IS NULL AND tIO2.PartNumber IS NOT NULL THEN tIO2.Qty
    ELSE 0
 END
FROM @MasterPLantParts mpp
LEFT JOIN twoInOne AS tIO
    ON mpp.PlantCode = tIO.PlantCode
    AND tIO.PlantCode IS NOT NULL
LEFT JOIN twoInOne AS tIO2
    ON mpp.PartNumber = tIO2.PartNumber
    AND tIO2.PlantCode IS NULL  
order by mpp.PlantCode, mpp.PartNumber

我不了解甲骨文，但我想这可能是这样的：

SELECT 
  mpp.PlantCode PlantCode, 
  mpp.PartNumber PartNumber,
  CASE 
    WHEN tIO.PlantCode IS NOT NULL THEN tIO.Qty
    WHEN tIO2.PlantCode IS NULL AND tIO2.PartNumber IS NOT NULL THEN tIO2.Qty
    ELSE 0
 END
FROM @MasterPLantParts mpp, 
    (SELECT MHP.PlantCode, MHL.PartNumber, SUM(MHL.Qty) AS Qty
    FROM @MHL MHL, @MHP MHP
    WHERE MHL.LineNumber = MHP.LineNumber(+)
    GROUP BY MHP.PlantCode, MHL.PartNumber
    ) tIO,
    (SELECT MHP.PlantCode, MHL.PartNumber, SUM(MHL.Qty) AS Qty
    FROM @MHL MHL, @MHP MHP
    WHERE MHL.LineNumber = MHP.LineNumber(+)
    GROUP BY MHP.PlantCode, MHL.PartNumber
    ) tIO2
WHERE mpp.PlantCode = tIO.PlantCode(+)
    AND mpp.PartNumber = tIO2.PartNumber(+)
    AND tIO.PlantCode IS NOT NULL
    AND tIO2.PlantCode IS NULL  
order by mpp.PlantCode, mpp.PartNumber

Answer 4

警告：未经测试，可能效率不高 - sqlfiddle无法正常工作

select mpp.PlantCode PlantCode, 
    mpp.PartNumber PartNumber,
    nvl(sum(MHL.Qty),0) as SumQty -- edit1: add nvl
from @MasterPLantParts mpp
left outer join @MHP MHP on mpp.PlantCode = MHP.PlantCode
left join @MHL MHL on (  -- edit2: from inner join to left join
        MHL.LineNumber = MHP.LineNumber 
    or (
        mpp.PartNumber = MHL.PartNumber
        and mpp.PartNumber not in ( 
            select MHL2.PartNumber 
            from @MHL MHL2 
            inner join @MHP mhp2 on MHL2.LineNumber = MHP2.LineNumber 
            where mhp2.PlantCode != mpp.PlantCode 
        )
    )
)
group by mpp.PlantCode, mpp.PartNumber
order by mpp.PlantCode, mpp.PartNumber

仅当表中没有其他相关条目时才获取总和

4 个答案: