Question

我试图在我的模板中显示下拉菜单，但是我收到以下错误

File "forms.py" in DropdownSelectionForm
  101.     selection = forms.ChoiceField(choices=MY_CHOICES, widget = Select)

Exception Type: NameError at /
Exception Value: name 'Select' is not defined

这是我试图显示表单的模板

 <form action="/doclistings/" method="post" >{% csrf_token %}
            <select class="form-control" id="s1" NAME="selection">
              <option><b>Find a Doctor...</b></option>
              {% for value, text in form.selection.field.choices %}
                <option value="{{ value }}">{{ text }}</option>
              {% endfor %}
            </select>

这是forms.py

MY_CHOICES = (
    ('Dermatologist', 'Dermatologist'),
    ('Dentist', 'Dentist'),
    ('Opthalmologist', 'Opthalmologist'),
)

class DropdownSelectionForm(forms.Form):
    selection = forms.ChoiceField(choices=MY_CHOICES, widget = Select)

Answer 1

与Python中的任何其他内容一样，您需要正确引用该对象。在这种情况下，Select通过表单模块提供，与ChoiceField完全相同。

selection = forms.ChoiceField(choices=MY_CHOICES, widget=forms.Select)

Answer 2

Python无法找到Select，我发现您已导入django.forms，因此请尝试widget=forms.Select

Django 1.6名称选择未定义

2 个答案: