Question

我正在尝试使用Django中的Tastypie Api更新对象，但我找不到任何方法来执行此操作...

我想发送一个像/ api / vote / pk = 3这样的网址，它会用pk = 3更新对象并增加投票编号字段......是否可以轻松完成？

先谢谢...

我只是尝试创建一个像这样的Ressource：但即使我不做任何处理它也不起作用。它需要定义obj_get_list等...

class IphoneVoteRessource(Resource): 
    id = fields.IntegerField(attribute='id') 
    name = fields.CharField(attribute='name') 

class Meta: 
    resource_name = 'poi_vote' 
    object_class = Row 

def obj_update(self, bundle, request=None, **kwargs): 
    # update an existing row 
    pk = int(kwargs['pk']) 
    return bundle `

我已经多次使用Tastypie获取数据，但从不更新一个对象..

Answer 1

我终于使用了ModelResource，如果有人想要一个有效的例子：

class VoteResourceAnonymous(ModelResource):

class Meta:
    queryset = VoteAnonymous.objects.all()
    resource_name = 'vote_object'
    # need to send 'vote_value' and 'object_id'
    excludes = ['created_at', 'content_type', 'content_object', 'user_agent', 'ip_address']
    allowed_methods = ['get', 'post', 'put', 'delete']
    always_return_data = True

def obj_create(self, bundle, request=None, **kwargs):

    vote_value = bundle.data['vote_value']
    object_id = bundle.data['object_id']

    tmp_poi = PointOfInterestActivity.objects.get(id=object_id)
    content_type_object = ContentType.objects.get_for_model(tmp_poi)

    bundle.obj = VoteAnonymous(vote_value=vote_value,
                               object_id=object_id,
                               user_agent="",
                               ip_address="",
                               content_type=content_type_object,
                               )

    bundle.obj.save()

    if vote_value > 0:
        bundle.data['new_nb_votes'] = tmp_poi.nb_votes + 1
    else:
        bundle.data['new_nb_votes'] = tmp_poi.nb_votes - 1

    return bundle

使用Tastypie Django更新对象

1 个答案: