Question

我正在尝试创建一个显示特定时间间隔内日期的查询。例如，如果我有一个hire_date且min（hire_date）是2009-01-01而max（hire_date）是2009-03-1，那么表格应该以2天的频率显示hire_date。像：

+---------+
hire_date 
+---------+
2009-01-01
2009-01-03
2009-01-05
2009-01-07
..........

名为Employee_Service的表包含：

ID Number
Hire_date Timestamp
Name Varchar

我使用的当前查询是：

select trunc(hire_date) "Date", 
       count(id) "Num Empl Opened"
from Employee_Service 
group by trunc(hire_date) 
order by trunc(hire_date)

有没有办法为此构建查询。

Answer 1

您可以尝试：

select trunc(hire_date) "Date",
       count(id) "Num Empl Opened"
from Employee_Service 
where mod(to_char(hire_date,'dd'),2)<>0
and trunc(hire_date) between to_date('2009-01-01','yyyy-mm-dd') and to_date('2009-03-01','yyyy-mm-dd')
group by trunc(hire_date)
order by trunc(hire_date)

Answer 2

试试这个：

WITH DAYS AS
(SELECT TRUNC(TO_DATE('2009-03-01','YYYY-mm-dd')) - ROWNUM*2 D
 FROM ALL_OBJECTS
 WHERE ROWNUM < 365)
SELECT
  DAYS.D
FROM
  DAYS WHERE D >= TO_DATE('2009-01-01','YYYY-mm-dd');

Demo

Answer 3

我想这样的查询可以帮到你

select to_date('01/05/2014','DD/MM/YYYY') + level -1 HIRE_DATE
from dual
WHERE MOD(LEVEL,2) <> 0
connect by level <= to_date('01/06/2014','DD/MM/YYYY') - to_date('01/05/2014','DD/MM/YYYY') +1;

WHERE '01 / 05/2014'从日期开始，'01/06 / 2014'截止日期。

所以你的查询是：

如果hire_date是DD / MM / YYYY格式的VARCHAR

select to_date(min(hire_date),'DD/MM/YYYY') + level -1 HIRE_DATE from dual WHERE MOD(LEVEL,2) <> 0 connect by level <= to_date(max(hire_date),'DD/MM/YYYY') - to_date(min(hire_date),'DD/MM/YYYY') +1;

或者，

如果HIRE_DATE是日期字段，

select (min(hire_date)) + level -1 HIRE_DATE from dual WHERE MOD(LEVEL,2) <> 0 connect by level <= (max(hire_date)) - (min(hire_date)) +1;

修改 Max和Min不能与Group by一起使用。所以请使用以下格式：

with cte as ( select max(hire_date) max_date, min(hire_date) min_date from my_table where --- all conditions here and rownum=1 ) select (min_date + level -1) hire_dates from dual WHERE MOD(LEVEL,2) <> 0 connect by level <= ( max_date - min_date +1 );

with cte as ( select max(hire_date) max_date, min(hire_date) min_date from Employee_Service ) select (min_date + level -1) "Date", count(id) "Num Empl Opened" from Employee_Service , cte WHERE MOD(LEVEL,2) <> 0 group by (min_date + level -1) connect by level <= ( max_date - min_date +1 ) ORDER BY (min_date + level -1);

固定频率上的SQL显示日期

3 个答案: