Question

我有一张像这样的表：

  Users:
--------------------------------------------------------------------------------
    User_id: User_name: User_email: User_has_neck: User_has_eyes: User_has_head: User_has_hair
    1      | John     | jon@jk.com| yes          | yes          |  sometimes   |  sometimes
    2      | Kate     | kte@jk.com| yes          | yes          |  sometimes   |  some
    3      | Mark     | mrk@jk.com| yes          | sometimes    |  sometimes   |  sometimes
    4      | Kora     | sometimes | yes          | yes          |  yes         |  some
    5      | Acts     | act@jk.com| sometimes    | sometimes    |  sometimes   |  some
    6      | Jerw     | sometimes | yes          | yes          |  yes         |  too_much
    7      | Dude     | sometimes | sometimes    | sometimes    |  yes         |  too_much
    8      | Ninja    | nja@kl.com| yes          | yes          |  yes         |  too_much

现在，我需要查询：

SELECT * FROM Users WHERE <NO_COLUMN_IS_EQUAL_TO_sometimes>;

列可能包含数据; 'yes'，'some'但NOT 'sometimes';

如何做到这一点？......任何建议都受到高度赞赏。

我试过了，

SELECT * FROM Users WHERE *#@!$%^()**#$ NO IDEA..... ＆＃39; ---------＆gt; stackOverflow＆＃39;

Answer 1

只需在where子句中进行显式比较即可。这是一个例子：

SELECT *
FROM Users
WHERE 'sometimes' not in (User_has_neck, User_has_eyes, User_has_head, User_has_hair);

编辑：

在您的示例中，您可以使用以下查询生成列表：

select group_concat(column_name separator ', ')
from information_schema.columns c
where table_name = 'users' and table_schema = ???;

如何使用适用于这些行中多个列的条件选择多个行？

1 个答案: