我正在使用WerbLogic 10.3.5和Spring 3.0来实现JMS队列。我有以下Spring配置:
<!-- JMS Configuration -->
<bean id="paymentlistener" class="com.myproject.service.impl.PaymentListener"/>
<bean id="paymentlistenerContainer" class="org.springframework.jms.listener.DefaultMessageListenerContainer">
<property name="concurrentConsumers" value="10"/>
<property name="connectionFactory" ref="paymentConnectionFactory"/>
<property name="destination" ref="paymentQueue"/>
<property name="messageListener" ref="paymentlistener"/>
</bean>
<bean id="paymentQueue" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="jms/paymentResponseHandlerQueue"/>
<property name="jndiTemplate" ref="jndiTemplate"/>
</bean>
<bean id="jndiTemplate" class="org.springframework.jndi.JndiTemplate">
<property name="environment">
<props>
<prop key="java.naming.factory.initial">weblogic.jndi.WLInitialContextFactory</prop>
<prop key="java.naming.provider.url">t3://localhost:7001</prop>
</props>
</property>
</bean>
<bean id="paymentConnectionFactory" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiTemplate" ref="jndiTemplate"/>
<property name="jndiName" value="jms/paymentResponseHandlerConnectionFactory"/>
</bean>
<bean id="jmsDestinationResolver" class="org.springframework.jms.support.destination.JndiDestinationResolver">
<property name="jndiTemplate" ref="jndiTemplate"/>
<property name="cache" value="true"/>
</bean>
<bean id="jmsTemplate" class="org.springframework.jms.core.JmsTemplate">
<property name="connectionFactory" ref="paymentConnectionFactory"/>
<property name="destinationResolver" ref="jmsDestinationResolver"/>
<property name="defaultDestination" ref="paymentQueue"/>
<property name="sessionAcknowledgeModeName" value="DUPS_OK_ACKNOWLEDGE"/>
<property name="sessionTransacted" value="true"/>
</bean>
我的消息创建代码如下所示:
MessageCreator messageCreator = new MessageCreator() {
public Message createMessage(Session session) throws JMSException {
logger.debug("Session ack mode: " + session.getAcknowledgeMode());
return session.createObjectMessage(payment);
}
};
jmsTemplate.send("jms/paymentResponseHandlerQueue", messageCreator);
我的听众看起来像这样:
@Override
public void onMessage(Message message) { // , Session session
if (!(message instanceof ObjectMessage)) {
throw new IllegalStateException("The PaymentListener queue expects an object message");
}
ObjectMessage objectMessage = (ObjectMessage) message;
try {
logger.debug("Is Message redelivered:" + objectMessage.getJMSRedelivered ());
if (objectMessage.getObject() instanceof CreditCardPaymentDTO) {
logger.debug("Object is of type CreditCardPaymentDTO");
// The user that just logged in
CreditCardPaymentDTO payment = (CreditCardPaymentDTO) objectMessage.getObject();
otpCollectorDAO.savePayment(payment);
}
} catch (JMSException e) {
logger.error(e);
throw new RuntimeException(e);
} catch (PaymentResponseException e) {
logger.error(e);
throw new RuntimeException(e);
}
}
正在正确创建消息,并且正在调用我的侦听器的onMessage()方法,但是如果逻辑失败并且我抛出RuntimeException(),则消息不会被重新传递。我尝试了上述代码的许多细微变化(例如,设置sessionAcknowledgeModeName = SESSION_TRANSACTED并显式回滚事务),但消息永远不会重新排队。将失败的消息转发给重新传递的技巧是什么?
答案 0 :(得分:3)
我认为您需要为sessionTransacted
设置true
到DefaultMessageListenerContainer
:
<bean id="paymentlistenerContainer" class="org.springframework.jms.listener.DefaultMessageListenerContainer">
...
<property name="sessionTransacted" value="true"/>
</bean>
您可以找到here相关参考文档。