尝试将作为参数传递的数组匹配到接收varargs数组的方法时,我遇到了问题。
其他问题/答案中提到的anyVararg()匹配器并不适合我,因为我想确保提供的数组是我需要的数组。
我将问题简化为这个更易于理解和抽象问题的例子(我的真正问题是生产代码并具有业务逻辑,因此对于这个问题的目的而言会令人困惑):
@RunWith(MockitoJUnitRunner.class)
public class UnitTest {
private Object[] objectArray;
private List<Object> expected;
private TestTarget target;
@Before
public void setUp() {
objectArray = new Object[]{ new Object() };
expected = Arrays.asList(new Object(), new Object());
target = Mockito.spy(new TestTarget());
}
@Test
public void testMakeList() { // this pass as eq works well with normal array
doReturn(expected).when(target).toList(Mockito.eq(objectArray));
Assert.assertEquals(expected, target.makeList(objectArray));
}
@Test
public void testMakeList1() { // this one fails as eq is not working with varargs
doReturn(expected).when(target).toList1(Mockito.eq(objectArray));
Assert.assertEquals(expected, target.makeList1(objectArray));
}
@Test
public void testMakeListWithAryEq() { // fails, aryEq is not working with varargs
doReturn(expected).when(target).toList1(AdditionalMatchers.aryEq(objectArray));
Assert.assertEquals(expected, target.makeList1(objectArray));
}
private class TestTarget {
public List<Object> makeList(Object[] objects) {
return toList(objects);
}
public List<Object> makeList1(Object[] objects) {
return toList1(objects);
}
protected List<Object> toList(Object[] objs) {
return null; // Not implemented "Intentionally"
}
protected List<Object> toList1(Object... objs) {
return null; // Not implemented "Intentionally"
}
}
}
当我在类中运行测试用例时,第一个测试用例将通过而不是其他两个,既不使用eq也不使用aryEq。显示以下跟踪:
java.lang.AssertionError: expected:<[java.lang.Object@56d5e457, java.lang.Object@7482384a]> but was:<null>
at org.junit.Assert.fail(Assert.java:88)
at org.junit.Assert.failNotEquals(Assert.java:743)
at org.junit.Assert.assertEquals(Assert.java:118)
at org.junit.Assert.assertEquals(Assert.java:144)
...
这是因为eq匹配器不使用varargs数组,是否有替代此用例的eq匹配器?
答案 0 :(得分:6)
好的,我认为这里的答案需要一个自定义构建的匹配器,可以在单元测试中实现,如下所示:
private class MyVarargMatcher extends ArgumentMatcher<Object[]> implements VarargMatcher {
private Object[] expectedValues;
MyVarargMatcher(Object... expectedValues) {
this.expectedValues = expectedValues;
}
@Override
public boolean matches(Object varargArgument) {
return new EqualsBuilder()
.append(expectedValues, varargArgument)
.isEquals();
}
}
然后,在testMakeList1()
中将第一行更改为:
Mockito.doReturn(expected).when(target).toList1(Mockito.argThat(new MyVarargMatcher(objectArray)));
来源:
How to properly match varargs in Mockito
http://maciejmadej.blogspot.com/2011/11/capturing-varargs-argument-using-custom.html
答案 1 :(得分:0)
匹配varargs没问题。唯一的限制是您必须将每个单独的数组条目指定为匹配的参数。我已经更新了下面的代码以显示我的意思。我创建了第二个objectArray2来使点更清晰。所有测试均通过:
@RunWith(MockitoJUnitRunner.class)
public class UnitTest {
private Object[] objectArray;
private Object[] objectArray2;
private List<Object> expected;
private TestTarget target;
private Object obj,obj2;
@Before
public void setUp() {
obj = new Object();
obj2 = new Object();
objectArray = new Object[]{ obj };
objectArray2 = new Object[]{ obj, obj2 };
expected = Arrays.asList(new Object(), new Object());
target = Mockito.spy(new TestTarget());
}
@Test
public void testMakeList() { // this pass as eq works well with normal array
doReturn(expected).when(target).toList(Mockito.eq(objectArray));
Assert.assertEquals(expected, target.makeList(objectArray));
}
@Test
public void testMakeList1() { // since objectArray has one entry you need to add one matching argument
doReturn(expected).when(target).toList1(Mockito.eq(obj));
Assert.assertEquals(expected, target.makeList1(objectArray));
}
@Test
public void testMakeListWithAryEq() { // since objectArray2 has two entries you need to add two matching arguments
doReturn(expected).when(target).toList1(Mockito.eq(obj),Mockito.eq(obj2));
Assert.assertEquals(expected, target.makeList1(objectArray2));
}
private class TestTarget {
public List<Object> makeList(Object[] objects) {
return toList(objects);
}
public List<Object> makeList1(Object[] objects) {
return toList1(objects);
}
protected List<Object> toList(Object[] objs) {
return null; // Not implemented "Intentionally"
}
protected List<Object> toList1(Object... objs) {
return null; // Not implemented "Intentionally"
}
}
}