我有一个名为Events的mongodb系列,包含棒球比赛。以下是表中一条记录的示例:
{
"name" : "Game# 814",
"dateStart" : ISODate("2012-09-28T14:47:53.695Z"),
"_id" : ObjectId("53a1b24de3f25f4443d9747e"),
"stats" : [
{
"team" : ObjectId("53a11a43a8de6dd8375c940b"),
"teamName" : "Reds",
"_id" : ObjectId("53a1b24de3f25f4443d97480"),
"score" : 17
},
{
"team" : ObjectId("53a11a43a8de6dd8375c938d"),
"teamName" : "Yankees",
"_id" : ObjectId("53a1b24de3f25f4443d9747f"),
"score" : 12
}
]
"__v" : 0
}
我需要帮助编写返回所有团队排名的查询。结果集应如下所示:
{
"team" : ObjectId("53a11a43a8de6dd8375c938d"),
"teamName" : "Yankees",
"wins" : <<number of Yankees wins>>
"losses" : <<number of Yankees losses>>
"draws" : <<number of Yankees draws>>
}
{
"team" : ObjectId("53a11a43a8de6dd8375c940b"),
"teamName" : "Reds",
"wins" : <<number of Reds wins>>
"losses" : <<number of Reds losses>>
"draws" : <<number of Reds draws>>
}
...
以下是我开始的查询...
db.events.aggregate(
{"$unwind": "$stats" },
{ $group : {
_id : "$stats.team",
gamesPlayed : { $sum : 1},
totalScore : { $sum : "$stats.score" }
}}
);
...返回结果:
{
"result" : [
{
"_id" : ObjectId("53a11a43a8de6dd8375c93cb"),
"gamesPlayed" : 125, // not a requirement... just trying to get $sum working
"totalScore" : 1213 // ...same here
},
{
"_id" : ObjectId("53a11a44a8de6dd8375c955f"),
"gamesPlayed" : 128,
"totalScore" : 1276
},
{
"_id" : ObjectId("53a11a44a8de6dd8375c9661"),
"gamesPlayed" : 152,
"totalScore" : 1509
},
....
答案 0 :(得分:1)
在您创建或更新文档时,您最好保留文档中的“胜利”,“损失”和“抽奖”。但是如果有点长篇大论的话,可以用聚合作为
db.events.aggregate([
// Unwind the "stats" array
{ "$unwind": "$stats" },
// Combine the document with new fields
{ "$group": {
"_id": "$_id",
"firstTeam": { "$first": "$stats.team" },
"firstTeamName": { "$first": "$stats.teamName" },
"firstScore": { "$first": "$stats.score" },
"lastTeam": { "$last": "$stats.team" },
"lastTeamName": { "$last": "$stats.teamName" },
"lastScore": { "$last": "$stats.score" },
"minScore": { "$min": "$stats.score" },
"maxScore": { "$max": "$stats.score" }
}},
// Calculate by comparing scores
{ "$project": {
"firstTeam": 1,
"firstTeamName": 1,
"firstScore": 1,
"lastTeam": 1,
"lastTeamName": 1,
"lastScore": 1,
"firstWins": {
"$cond": [
{ "$gt": [ "$firstScore", "$lastScore" ] },
1,
0
]
},
"firstLosses": {
"$cond": [
{ "$lt": [ "$firstScore", "$lastScore" ] },
1,
0
]
},
"firstDraws": {
"$cond": [
{ "$eq": [ "$firstScore", "$lastScore" ] },
1,
0
]
},
"lastWins": {
"$cond": [
{ "$gt": [ "$lastScore", "$firstScore" ] },
1,
0
]
},
"lastLosses": {
"$cond": [
{ "$lt": [ "$lastScore", "$firstScore" ] },
1,
0
]
},
"lastDraws": {
"$cond": [
{ "$eq": [ "$lastScore", "$firstScore" ] },
1,
0
]
},
"type": { "$literal": [ true, false ] }
}},
// Unwind the "type"
{ "$unwind": "$type" },
// Group teams conditionally on "type"
{ "$group": {
"_id": {
"team": {
"$cond": [
"$type",
"$firstTeam",
"$lastTeam"
]
},
"teamName": {
"$cond": [
"$type",
"$firstTeamName",
"$lastTeamName"
]
}
},
"owins": {
"$sum": {
"$cond": [
"$type",
"$firstWins",
"$lastWins"
]
}
},
"olosses": {
"$sum": {
"$cond": [
"$type",
"$firstLosses",
"$lastLosses"
]
}
},
"odraws": {
"$sum": {
"$cond": [
"$type",
"$firstDraws",
"$lastDraws"
]
}
}
}},
// Project your final form
{ "$project": {
"_id": 0,
"team": "$_id.team",
"teamName": "$_id.teamName",
"wins": "$owins",
"losses": "$olosses",
"draws": "$odraws"
}}
])
第一部分是通过展开数组来“重新塑造”文档,然后使用“first”和“last”进行分组,以便为两个团队定义字段。
然后你希望通过这些文件$project
计算你的“胜利”,“损失”和“抽奖”。另外一件事是为这两个值true/false
添加一个数组字段很方便。如果您使用的是mongodb的2.6之前的版本,$literal
可以替换为 $const
,但未记录在案,但会做同样的事情。
一旦你$unwind
那个“类型”数组,通过评估是否通过使用选择“第一个”或“最后一个”团队字段值,可以在$group
阶段拆分文档$cond
。这是一个三元运算符,用于计算true/false
条件并根据该条件返回适当的值。
通过最终$project
,您的文档将按照您想要的方式形成。