Question

我正在努力格式化我的json数据。我希望它看起来像这样。我已经遍布stackoverflow和互联网，无法找到一个有效的功能。我使用的每个函数都导致原始json数据的格式保持不变。

[
    {
        "id": 1,
        "name": "Kenneth Auchenberg",
        "avatar": "http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif",
        "type": "contact"
    },
    {
        "id": 2,
        "name": "Jon Froda",
        "avatar": "http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif",
        "type": "contact"
    },
    {
        "id": 3,
        "name": "Anders Pollas",
        "avatar": "http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif",
        "type": "contact"
    },

]

但是，它会像这样继续打印：

{"id":"4","name":"Kenneth Auchenberg"}

我已经尝试了所有在线功能，但无济于事。这是我目前的代码：

<?php
$mysql_hostname = "localhost";
$mysql_user = "root";
$mysql_password = "root";
$mysql_database = "students";

$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Opps some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Opps some thing went wrong");



$sql_in= mysql_query("SELECT name,id FROM users order by name desc");
while($row = mysql_fetch_array($sql_in))
{
$name=$row['name'];
$id=$row['id'];


$variable = array( 'id' => "$id", 
                       'name' => "$name" );

}
$json = json_encode($variable);

    echo $json;
?>

Answer 1

您只需在每次循环迭代时覆盖$variable值。这是一个简单的改变。只需确保将在循环中创建的数组放入$variable中的新数组位置，如下所示：

$variable[] = array(...);

Answer 2

使用此代码可能会对您有所帮助

     while($row = mysql_fetch_array($sql_in))
        {
        $name=$row['name'];
        $id=$row['id'];


   $variable[] = array( 'id' => "$id",'name' => "$name" );//use $variable[] instead of $variable

        }
    echo $json = json_encode($variable);

Answer 3

像这样

初始化体外的$变量

$variable = array();
$sql_in= mysql_query("SELECT name,id FROM users order by name desc");
while($row = mysql_fetch_array($sql_in))
{
    $name=$row['name'];
    $id=$row['id'];
    $variable[] = array( 'id' => "$id", 'name' => "$name" );
}

以自定义格式获取json数据

3 个答案: